The confidence interval for the difference p1 - p2 of the population proportion is (0.063, 0.329)
<h3>How to determine the confidence interval?</h3>
The given parameters are:
n₁ = 93; n₂ = 80
p₁ = 0.814; p₂ = 0.618
The critical value at 95% confidence interval is
z = ±1.96
So, we have:

Substitute known values in the above equation

Evaluate

This gives
CI = 0.196 ± 0.133
Expand
CI = (0.196 - 0.133, 0.196 + 0.133)
Evaluate
CI = (0.063, 0.329)
Hence, the confidence interval is (0.063, 0.329)
Read more about confidence interval at:
brainly.com/question/15712887
#SPJ1
Answer:
uhm i can't see the bottom of the graph but if u look where it says 200 on the cash side u go up halfway to 240 making it meet the limit of 220? so then u go all the way left until u hit the orange line and when u hit it u go straight down giving u the answer
Step-by-step explanation:
74
Because 3x3 = 9, multiply first then add, so 2+(9x8) = 74