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3 years ago

If x° and 54° form a linear pair find x°

Mathematics

2 answers:

elixir [45]3 years ago

6 0

Answer:

x = 126°

Step-by-step explanation:

x + 54 = 180°

x + 54 - 54 = 180 - 54

x = 126°

jeka57 [31]3 years ago

3 0

Answer:

x= 126°

Step-by-step explanation:

180-54

126°

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2. Find the perimeter of a rectangle which has a length of 3.2 cm and a width of 1.6 cm.

Elodia [21]

Answer:

9.6

Step-by-step explanation:

you would do 3.2+3.2, which equals 6.4. Then you would do 1.6+1.6 which is 3.2. Add 6.4 and 3.2 and you get 9.6

8 0

4 years ago

(90 points) what's the area of a 5m circle , 50 mm circle , 40in circle , 7ft circle, 21mm circle and a 70cm circle all using 3.

Xelga [282]

Answers:

AREA OF A CIRCLE = pi x r^2

5m circle:

when it says 5 i think it means diameter so divide by 2 for radius

5/2 = 2.5

3.14 x 2.5^2=

3.14 x 6.25=

19.625m^2

50mm circle:

50/2= 25

3.14 x 25^2=

3.14 x 625=

1962.5mm^2

40in circle:

40/2= 20

3.14 x 20^2 =

3.14 x 400=

1256in^2

7ft circle:

7/2= 3.5

3.14 x 3.5^2=

3.14 x 12.25=

38.465ft^2

21mm circle:

21/2= 10.5

3.14 x 10.5^2=

3.14 x 110.25=

346.185mm^2

70cm circle:

70/2=35

3.14 x 35^2=

314 x 1225=

3846.5cm^2

Hope that helps :)

4 0

2 years ago

John ordered three lobsters.the fist one weighed 3.2 pounds,the second weighted 1.75 pounds,the third 1.9 pounds what is the tot

Nadusha1986 [10]

Add them all up, 3.2 + 1.75 + 1.9 = 6.85

The total weight is 6.85 pounds.

4 0

3 years ago

Solve 3x + k = cfor x.

Ghella [55]

First, subtract k from both sides. That means c - k is in the left side and 3x is on the right. Then, divide by 3 on both sides. So, the answer is x = (c - k) / 3.

7 0

3 years ago

GIVING OUT BRAINLIEST TO WHOEVER GETS ALL OF THEM RIGHT

Thepotemich [5.8K]

Answer:

4) $\frac{x}{7\cdot x +x^{2}}$ is equivalent to $\frac{1}{7+x}$ for all $x \ne -7$ . (Answer: A)

5) $\frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}$ is equivalent to $-\frac{14}{1-5\cdot x}$ for all $x \ne \frac{1}{5}$ . (Answer: B)

6) $\frac{x+7}{x^{2}+4\cdot x - 21}$ is equivalent to $\frac{1}{x-3}$ for all $x \ne 3$ . (Answer: None)

7) $\frac{x^{2}+3\cdot x -4}{x+4}$ is equivalent to $x - 1$ . (Answer: None)

8) $\frac{2}{3\cdot a}\cdot \frac{2}{a^{2}}$ is equivalent to $\frac{4}{3\cdot a^{3}}$ for all $a\ne 0$ . (Answer: A)

Step-by-step explanation:

We proceed to simplify each expression below:

4) $\frac{x}{7\cdot x +x^{2}}$

(i) $\frac{x}{7\cdot x +x^{2}}$ Given

(ii) $\frac{x}{x\cdot (7+x)}$ Distributive property

(iii) $\frac{1}{7+x} \cdot \frac{x}{x}$ Distributive property

(iv) $\frac{1}{7+x}$ Existence of multiplicative inverse/Modulative property/Result

Rational functions are undefined when denominator equals 0. That is:

$7+x = 0$

$x = -7$

Hence, we conclude that $\frac{x}{7\cdot x +x^{2}}$ is equivalent to $\frac{1}{7+x}$ for all $x \ne -7$ . (Answer: A)

5) $\frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}$

(i) $\frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}$ Given

(ii) $\frac{x^{3}\cdot (-14)}{x^{3}\cdot (1-5\cdot x)}$ Distributive property

(iii) $\frac{x^{3}}{x^{3}} \cdot \left(-\frac{14}{1-5\cdot x} \right)$ Distributive property

(iv) $-\frac{14}{1-5\cdot x}$ Commutative property/Existence of multiplicative inverse/Modulative property/Result

Rational functions are undefined when denominator equals 0. That is:

$1-5\cdot x = 0$

$5\cdot x = 1$

$x = \frac{1}{5}$

Hence, we conclude that $\frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}$ is equivalent to $-\frac{14}{1-5\cdot x}$ for all $x \ne \frac{1}{5}$ . (Answer: B)

6) $\frac{x+7}{x^{2}+4\cdot x - 21}$

(i) $\frac{x+7}{x^{2}+4\cdot x - 21}$ Given

(ii) $\frac{x+7}{(x+7)\cdot (x-3)}$ $x^{2} -(r_{1}+r_{2})\cdot x +r_{1}\cdot r_{2} = (x-r_{1})\cdot (x-r_{2})$

(iii) $\frac{1}{x-3}\cdot \frac{x+7}{x+7}$ Commutative and distributive properties.

(iv) $\frac{1}{x-3}$ Existence of multiplicative inverse/Modulative property/Result

Rational functions are undefined when denominator equals 0. That is:

$x-3 = 0$

$x = 3$

Hence, we conclude that $\frac{x+7}{x^{2}+4\cdot x - 21}$ is equivalent to $\frac{1}{x-3}$ for all $x \ne 3$ . (Answer: None)

7) $\frac{x^{2}+3\cdot x -4}{x+4}$

(i) $\frac{x^{2}+3\cdot x -4}{x+4}$ Given

(ii) $\frac{(x+4)\cdot (x-1)}{x+4}$ $x^{2} -(r_{1}+r_{2})\cdot x +r_{1}\cdot r_{2} = (x-r_{1})\cdot (x-r_{2})$

(iii) $(x-1)\cdot \left(\frac{x+4}{x+4} \right)$ Commutative and distributive properties.

(iv) $x - 1$ Existence of additive inverse/Modulative property/Result

Polynomic function are defined for all value of $x$ .

$\frac{x^{2}+3\cdot x -4}{x+4}$ is equivalent to $x - 1$ . (Answer: None)

8) $\frac{2}{3\cdot a}\cdot \frac{2}{a^{2}}$

(i) $\frac{2}{3\cdot a}\cdot \frac{2}{a^{2}}$

(ii) $\frac{4}{3\cdot a^{3}}$ $\frac{a}{b}\cdot \frac{c}{d} = \frac{a\cdot b}{c\cdot d}$ /Result

Rational functions are undefined when denominator equals 0. That is:

$3\cdot a^{3} = 0$

$a = 0$

Hence, $\frac{2}{3\cdot a}\cdot \frac{2}{a^{2}}$ is equivalent to $\frac{4}{3\cdot a^{3}}$ for all $a\ne 0$ . (Answer: A)

6 0

3 years ago

If x° and 54° form a linear pair find x°​

If x° and 54° form a linear pair find x°