If 1/3x =10, what is 2/3x

Mathematics

1 answer:

ANTONII [103]3 years ago

4 0

The answer is 6 2/3

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I need help with these two trigonometry problems.

Sloan [31]

Answer:

$B \approx 32.1\°; A \approx 39.0\°$

Step-by-step explanation:

Sine theorem: in any triangle, the ratio between a side and the sine of the opposite angle is constant

$\frac{sin\ \alpha}a = \frac{sin\ \beta}b =\frac{sin\ \gamma}c$

In our case, for the left triangle,

$\frac {sin\ 103\°}{11} =\frac{sin\ B} 6 \rightarrow sin\ B = \frac6{11} sin\ 103\°$

Time to grab a calculator and crunch numbers. Double check your calculator is in degrees and not in radians (plug in sin 30°, if you're getting 0.5 you're good) and you will get

$sin\ B \approx 0.53 \rightarrow B \approx 32.1\°$

Same difference with the right triangle. With the same calculations

$sin\ A = \frac{26}{41} sin 83\° \approx 0.68 \rightarrow A \approx 39.0\°$

5 0

2 years ago

I will give lots of points please help

creativ13 [48]

Answer:

yes it is a right triangle if you look closely at triangle ABC there is a right triangle mark the little square

3 0

2 years ago

Read 2 more answers

Triangle ABC has points A(4,2) B(4,4) & C (0,4). If triangle ABC is dilated by a scale factor of 3 from the point (-1, 2) to

Snezhnost [94]

9514 1404 393

Answer:

A'(14, 2)

Step-by-step explanation:

The y-value of A is the same as the y-value of the center of dilation, so it remains unchanged.

The x-value of A is 4-(-1) = 5 units from the center of dilation, so A' will be 15 units from the center of dilation. 15 +(-1) = 14. The coordinates of A' are (14, 2).