Calculate the length of AC to one decimal place in the trapezium below.
1 answer:
Answer:
First we will split trapezium on two geometric figure.
One is rectangle and the second is right triangle.
When we subtract 11-4=7cm we get one cathetus of the right triangle a=7cm also we know hypotenuse which is c=16cm.
We will use Pythagorean theorem to find the second cathetus b
b=√16∧2-7∧2= √256-49= √207 ≈ 14.39cm =DC =>
AC =√(DC)∧2+(AD)∧2= √14.39∧2+11∧2= √207+121= √328= 18.1cm
AC=18.1cm
Good luck!!
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