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Sergeu [11.5K]
3 years ago
11

Calculate the length of AC to one decimal place in the trapezium below.

Mathematics
1 answer:
a_sh-v [17]3 years ago
7 0

Answer:

First we will split trapezium on two geometric figure.

One is rectangle and the second is right triangle.

When we subtract 11-4=7cm  we get one cathetus of the right triangle a=7cm also we know hypotenuse which is c=16cm.

We will use Pythagorean theorem to find the second cathetus b

b=√16∧2-7∧2= √256-49= √207 ≈ 14.39cm =DC =>

AC =√(DC)∧2+(AD)∧2= √14.39∧2+11∧2= √207+121= √328= 18.1cm

AC=18.1cm

Good luck!!

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(xₚ, yₚ) = ((x₁ + x₂)/2, (y₁ + y₂)/2)

(xₚ, yₚ) = ((-6 - 2)/2, (-4 + 1)/2)

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===============

Step 2. Find the <em>slope (m₁) of the segment</em>

m₁ = (y₂ - y₁)/(x₂ - x₁)

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m₁ = 5/4

===============

Step 3. Find the <em>slope (m₂) of the perpendicular bisector </em>

m₂ = -1/m₁

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====================

Step 4. Find the <em>intercept of the perpendicular bisector</em>

y = mx + b

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-3/2 = -(4/5)(-4) + b

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 -47 = 10b             Divide each side by 10

    b = -47/10

===============

Step 5. Write the <em>equation for the perpendicular bisector</em>

y = -4/5x – 47/10

The graph shows the midpoint of your segment at (-4, -3/2) and the perpendicular bisector passing through the midpoint and (0, -47/10).

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