A 4 cm × 6 cm 4cm×6cmstart color #1fab54, 4, start text, c, m, end text, times, 6, start text, c, m, end text, end color #1f
Andreas93 [3]
Answer:
- Area of the rectangle: 24 cm²
- Area of the circle: 380.13 cm²
- Area of between the circle and the rectangle: 356.13 cm²
Explanation:
The question describes<em> a rectangle of dimensions 4 cm × 6 cm inscribed in a circle with radius 11 cm</em>.
You can find:
- The area of the rectangle
- The area of the circle
- The area between the rectangle and the circle.
<u>1. Area of the rectangle:</u>
<u>2. Area of the circle:</u>
<u>3. Area between the rectangle of the circle:</u>
This is the area of the circle that does not belong to (or is outside of) the area of the rectangle.
Choose choice 3. It will pass through (-2,2) and will be parallel to the equation in the question.
ANSWER CHOICE 3 IS THE ANSWER
Answer: b) ΔADC ≡ ΔBCD by SAS
<u>Step-by-step explanation:</u>
Step 1: AD = BC SIDES are congruent
Step 2: ∠ADC ≡ ∠BCD ANGLES are congruent
Step 3: DC = DC SIDES are congruent
The proof is using Side-Angle-Side (SAS)
Look at the angles in step 2. These are the triangles you are proving congruency for: ΔADC ≡ ΔBCD
<h2>
Answer:</h2>
The method suggested by Bobby is better than Allie.
<h2>
Step-by-step explanation:</h2>
A fair sample is a sample where each sample has an equal opportunity to get selected for any survey.
Here, in the given question, Allie suggested that the first 3 students to arrive in class the next day should be the representatives. This sample is not random or fair.
Whereas, Bobby suggested that each student roll 2 numbers cubes and the 3 students with the highest sum should be the representatives. This method is a fair method.
The method suggested by Bobby is better than Allie as every student will get an equal chance to perform and also has an equal chance to win and get a high sum.
Answer:
Step-by-step explanation:
Given:
using the properties of log we can take the power 1/2 and multiply it.
now we can differentiate:
this is our answer!
