Answer:
t = sqrt(500/4.9) =~ 10.1 seconds/
Answer: 10.1015 seconds (this is approximate)
Step-by-step explanation:
Use 4.9t^2 + v0t = s
a) A bolt falls off an airplane at an altitude of 500 m. Approximately how long does it take the bolt to reach the ground?
s = 4.9t^2 + v0t = 500
4.9t^2 = 500
t = sqrt(500/4.9) =~ 10.1 seconds
Part A)
v = initial velocity = 0
s = 500 = vertical distance the object travels (from plane to ground)
Plug in the given values and solve for t
4.9t^2 + v*t = s
4.9t^2 + 0*t = 500
4.9t^2 + 0 = 500
4.9t^2 = 500
t^2 = 500/4.9
t^2 = 102.04081632653
t = sqrt(102.04081632653)
t = 10.101525445522
t = 10.1015
Answer: 10.1015 seconds (this is approximate)
Answer:
7a-7
Step-by-step explanation:
2a+2−3a−5+a−4+7a.
Combine like terms
2a-3a+a+7a+2-5-4
7a-7
Answer:
The equation would be y = 2x + 3
Step-by-step explanation:
In order to solve this, we first need to find the slope of the line between (-2, 5) and (2, 3). In order to do this, we use the slope formula.
m(slope) = (y2 - y1)/(x2 - x1)
m = (3 - 5)/(2 - -2)
m = -2/4
m = -1/2
Now that we have the original line with a slope of -1/2, we can tell a perpendicular line would have a slope of 2. This is because perpendicular lines have opposite and reciprocal slopes. Now we can use that slope and the given point in point-slope form to get the answer. Be sure to solve for y.
y - y1 = m(x - x1)
y + 7 = 2(x + 5)
y + 7 = 2x + 10
y = 2x + 3
Answer:
−35.713332 ; 0.313332
Step-by-step explanation:
Given that:
Sample size, n1 = 11
Sample mean, x1 = 79
Standard deviation, s1 = 18.25
Sample size, n2 = 18
Sample mean, x2 = 96.70
Standard deviation, s2 = 20.25
df = n1 + n2 - 2 ; 11 + 18 - 2 = 27
Tcritical = T0.01, 27 = 2.473
S = sqrt[(s1²/n1) + (s2²/n2)]
S = sqrt[(18.25^2 / 11) + (20.25^2 / 18)]
S = 7.284
(μ1 - μ2) = (x1 - x2) ± Tcritical * S
(μ1 - μ2) = (79 - 96.70) ± 2.473*7.284
(μ1 - μ2) = - 17.7 ± 18.013332
-17.7 - 18.013332 ; - 17.7 + 18.013332
−35.713332 ; 0.313332
