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3 years ago

PLEASE HELP ASAP

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

3 0

Answer:

(i) Drain water from the aquarium by 2 gallons.

(ii) Let evaporate 2 gallons of water.

Step-by-step explanation:

The water of the amount 2 gallons is added to a fish aquarium by a man. Then it was observed that the pool was too full and the water level needed to bring back down.

Now, there are few ways to bring the water level back to its previous level.

Options :

(i) Drain water from the aquarium by 2 gallons.

(ii) Let evaporate 2 gallons of water.

(Answer)

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A rectangle. one side is 2x + 7 and the other is x+3

saveliy_v [14]

$\large{\green}\fcolorbox{purple}{pink}{\bf{\underline{\red{\color{red}Answer}}}}$

6x + 20

Step-by-step explanation:

To find :-

Perimeter of rectangle

Given :-

Length = 2x + 7

Breadth/width = x + 3

Solution :-

We know that

$\mathfrak {perimeter \: of \: rectangle =2(length + breadth) }$

Now we will substitute the values of length and breadth

$\sf \longmapsto perimeter = 2 \{(2x + 7) + (x + 3) \} \\ \\ \\ \sf \longmapsto perimeter = 2 \{3x + 10 \} \\ \\ \\ \sf \longmapsto perimeter = 6x + 20$

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2 years ago

PLZZZ help 50 pts

IrinaK [193]

(5,2) because of the cordainte plane x axais is down and its positive so you get 5,2

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4 years ago

Read 2 more answers

What word expression matches 3+(4×12)

AnnyKZ [126]

The Word Expression Would Be:

Four times twelve plus three

Any Additional Questions? Comment Below!

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3 years ago

What 1 - 2/9 - 1/3 - 1/6 =

jek_recluse [69]

Answer:

5/18

Step-by-step explanation:

The LCD of 9, 3, and 6 is 18.

1 - 2/9 - 1/3 - 1/6 =

= 18/18 - 4/18 - 6/18 - 3/18

= 5/18

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2 years ago

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1.Solve the differential equation dy/dx= y^2/x^3 for y=f(x) with the condition y(1) = 1.

Elza [17]

This ODE is separable, so you can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2}{x^3}\iff\dfrac{\mathrm dy}{y^2}=\dfrac{\mathrm dx}{x^3}$

Integrating both sides gives

$-\dfrac1y=-\dfrac1{2x^2}+C$

and given the initial condition $y(1)=1$ , you have

$-\dfrac11=-\dfrac1{2(1)^2}+C\implies C=-\dfrac12$

so that the solution is

$-\dfrac1y=-\dfrac1{2x^2}-\dfrac12\implies y=\dfrac1{\frac1{2x^2}+\frac12}=\dfrac{2x^2}{1+x^2}$

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4 years ago