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Kruka [31]
3 years ago
14

Combine the following expressions. Answer right pls, thanks

Mathematics
1 answer:
Mama L [17]3 years ago
5 0

a) First of all, to combine the expressions we should simplify the surds as much as possible. I will break this simplification up for each term:

1. √(48n^3) = √( (4n)^(2) * 3n)

= 4n√(3n)

Here, the key is to ask yourself, what in the surd can be broken up into an even power?

Given that we have 48, we can say that 48 = 16*3 = 4^(2)*3.

We also have n^3 = n^(2)*n.

Together, 4^(2) and n^(2) can be written as (4n)^2, whilst 3 and n can be written as 3n.

Since the square root of a value squared is that value, we can then extract 4n from under the square root, and are left with 3n under the square root. Thus we have √(48n^3) = 4n√(3n)

2. Now we apply the same principle to the second surd:

√(9n) = √3^(2)*n

= 3√n

3. The third surd, √(3n), is a case where you cannot simplify any further.

b) Now that we have simplified each of the surds as much as possible, let us write out the simplified equation:

√(48n^3) + √(9n) - √(3n) = 4n√(3n) + 3√(n) - √(3n)

c) Since the terms 4n√(3n) and -√(3n) have a common factor of √(3n), we can combine them into (4n - 1)√(3n).

Note that there is a -1 in the bracket since -√(3n) is effectively equal to -1√(3n).

d) Now that we have combined those two terms, we may write out the combined expression in full:

4n√(3n) + 3√(n) - √(3n) = (4n - 1)√(3n) + 3√(n)

Thus, the second answer is correct.

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Can anyone help me?!
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Solve the system of equations <br> y=2x+4 <br> y=x^2+x-2
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Answer:

The two intersections would be (3, 10) and (-2, 0)

Step-by-step explanation:

To solve this system of equations, set the two equations equal to each other and solve for x.

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Now set the parenthesis equal to zero to get the x values.

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y = 6 + 4

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3 years ago
Find the recurrence relation satisfied by rn, where rn is the number of regions that a plane is divided into by n lines, if no t
joja [24]
1. Take a look at the pictures attached.

2. 

i) the first line divides the plane into 2 regions 

ii) the second line adds 2 more regions so we have 4 in total.

iii) the third line adds 3 more regions, so 4+3=7 regions

iv) the fourth line adds 4 more regions.

so the n^{th} line adds n more regions to the ones created by the previous n-1 lines.

3. 

r_1=2

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r_4=7+4=11

r_n=r_n_-_1+n

So the recurrence relation is

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3 years ago
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Ray Of Light [21]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
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