Answer:
Numerator , 0
Anything divided by 0 is always 0
Brainliest Pls
Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Begin with the right hand side:
R.H.S = cot θ =
L.H.S = sin θ cos θ
so, sin θ cos θ ≠ 
So, the equation is not a trigonometric identity.
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<u>Anther solution:</u>
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
Consider a function f(x), the linear approximation L(x) of f(x) is given by

Given the quantity:

We approximate the quantity using the function

, where x = 203.
We choose a = 200, thus the linear approximation is given as follows:
Answer:
f(2) 6x2= 12
f(-6) 6x-6=-36
f(5) 6x5=30
f(0) 6x0=0
f(10) 6x10=60
Step-by-step explanation:
it's really easy when they ask you this just put the number in parentheses instead of the x because x is an unknown number it's telling you to multiply the 6 by the number they give you