I dont undertand the go negative for the x and y but i can't read that so pick the -x,-y or something
Tenth term in A is -39366 but B isn’t a sequence or series
Answer:
L = 50 * (-0.4)^(n - 1)
Step-by-step explanation:
r = t2/t1 = -20/50 = - 0.4
a = 50
L = 50 * (r)^(n - 1) Let's see if we can get the answer when n = 3
L=50 * (-0.4)^(3 -1)
L =50* (-0.4)^2
L = 50 * 0.16
L = 8 which is correct
Answer:
Ok, we have:
d(t) = 3*t^2 + 5*t - 2.
The first interval is:
(2, 3)
and remember that, for an interval (a,b), the difference quotient is:
D = (f(b) - f(a))/(b -a)
Then in this first interval we have:
![d = \frac{d(3) - d(2)}{3-2} = \frac{3*3^2 + 5*3 - 2 - (3*2^2 + 5*2 - 2)}{1} = 20](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7Bd%283%29%20-%20d%282%29%7D%7B3-2%7D%20%20%3D%20%5Cfrac%7B3%2A3%5E2%20%2B%205%2A3%20-%202%20-%20%283%2A2%5E2%20%2B%205%2A2%20-%202%29%7D%7B1%7D%20%3D%2020)
So the average rate of change in (2,3) is 20.
now, in (2, 2.5) we have:
![d = \frac{d(2.5) - d(2)}{3-2} = \frac{3*2.5^2 + 5*2.5 - 2 - (3*2^2 + 5*2 - 2)}{1} = 9.25](https://tex.z-dn.net/?f=d%20%20%3D%20%5Cfrac%7Bd%282.5%29%20-%20d%282%29%7D%7B3-2%7D%20%20%3D%20%5Cfrac%7B3%2A2.5%5E2%20%2B%205%2A2.5%20-%202%20-%20%283%2A2%5E2%20%2B%205%2A2%20-%202%29%7D%7B1%7D%20%3D%209.25)
So here the rate of change is 9.25
And in the interval (2, 2.1) we have:
![d = \frac{d(2.1) - d(2)}{3-2} = \frac{3*2.1^2 + 5*2.1 - 2 - (3*2^2 + 5*2 - 2)}{1} = 1.73](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7Bd%282.1%29%20-%20d%282%29%7D%7B3-2%7D%20%20%3D%20%5Cfrac%7B3%2A2.1%5E2%20%2B%205%2A2.1%20-%202%20-%20%283%2A2%5E2%20%2B%205%2A2%20-%202%29%7D%7B1%7D%20%3D%201.73)
So in this interval the rate of change is 1.73
Answer:
x = 130 degrees
Step-by-step explanation:
We know that the total angle equals to 180 degrees since it is a straight line
Therefore, 25 + 25 + x = 180
180 - 25 - 25 = 130
Therefore, x = 130 degrees
Plz mark brainliest :D