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2 years ago

What is the slope of a line that passes through the points (5,-2) and (-3, -4)?

Mathematics

1 answer:

dedylja [7]2 years ago

4 0

Answer:

______________the answer is Y=0.25X-3.25_______

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2 x + 5 = 27 solve for x

Mnenie [13.5K]

Answer:

x=11

Step-by-step explanation:

2x+5=27

Subtract 5 on both side of 27

You will get 2x=22

Then divide it by 2

You will get x=11

8 0

3 years ago

Read 2 more answers

George was reading a mystery story. He read 42 pages in one hour. At this rate how many pages can he read in 40 minutes?

Viefleur [7K]

Answer:

56.8

Step-by-step explanation:

Ratios.

42------60

1----------1.42

40-------56.8

First, divide 42 by 42 which is one. Then, divide 60 by 42, which is 1.42.

Next, multiply 1 by 40. Finally multiply 1.42 by 40 which is 56.8. Hope this helps

5 0

3 years ago

What means lateral in math

Len [333]

Lateral surface area is the sum of all sides of a 3D object EXCEPT it's top and bottom bases.

7 0

3 years ago

What is the transformation shown?

natta225 [31]

5 units left and 1 unit up

4 0

3 years ago

What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?

telo118 [61]

Answer:

$f(x)=-\frac{1}{8}(x-3)^2+3$

Step-by-step explanation:

We want to find the equation of the parabola with a focus of $(3,1)$ and directrix $y=5$ .

Considering the directrix, the quadratic graph must open downwards.

The equation of this parabola is given by the formula,

$(x-h)^2=4p(y-k)$ , where $(h,k)$ is the vertex of the parabola.

The axis of this parabola meets the directrix at $(3,5)$ .

Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,

$h=\frac{3+3}{2}=3$ and $k=\frac{5+1}{2}=3$ .

The equation of the parabola now becomes,

$(x-3)^2=4p(y-3)$ .

Also $|p|$ is the distance between the vertex and the directrix.

$|p|=2$

This implies that $p=-2\:or\:2$ .

Since the parabola turns downwards,

$p=-2$ .

Our equation now becomes,

$(x-3)^2=4(-2)(y-3)$ .

$(x-3)^2=-8(y-3)$ .

We make y the subject to get,

$y=-\frac{1}{8}(x-3)^2+3)$ .

This is the same as

$f(x)=-\frac{1}{8}(x-3)^2+3)$ .

4 0

2 years ago