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Otrada [13]
3 years ago
11

A cross country racer records a time of exactly 4 minutes to complete a race that is a distance of 1,000 meters. What is the rac

er's speed, in meters/second, during the race?
Mathematics
1 answer:
lions [1.4K]3 years ago
6 0

Answer:

.24 meters/second

Step-by-step explanation:

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A function which has a constant difference per interval is?
QveST [7]

Answer:

I think A or C I'm not sure tho

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3 years ago
Find the distance between the pair of points and then round your answer to the nearest tenth.
Travka [436]

Answer:

d = 9.4 units (nearest tenth)

Step-by-step explanation:

Given the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}, distance between (-4, 5) and (4, 0) is calculated as follows:

Let (-4, 5) = (x_1, y_1)

(4, 0) = (x_2, y_2)

d = \sqrt{(4 - (-4))^2 + (0 - 5)^2}

d = \sqrt{(8)^2 + (- 5)^2}

d = \sqrt{64 + 25}

d = \sqrt{89}

d = 9.4 units (nearest tenth)

3 0
3 years ago
2. Draw the image of RST under the dilation with scale factor 2/3 and center of dilation (1,-1). Label the image RST .
professor190 [17]

Answer:

From the graph: we have the coordinates of RST i.e,

R = (2,1) , S = (2,-2) , T = (-1,-2)

Also, it is given the scale factor \frac{2}{3} and center of dilation C (1,-1)

The mapping rule for the center of dilation applied for the triangle as shown below:

(x, y) \rightarrow (\frac{2}{3}(x-1)+1, \frac{2}{3}(y+1)-1)

or

(x, y) \rightarrow (\frac{2}{3}x -\frac{2}{3}+1 , \frac{2}{3}y+\frac{2}{3}-1)

or

(x, y) \rightarrow (\frac{2}{3}x+\frac{1}{3} , \frac{2}{3}y-\frac{1}{3} )

Now,  

for R = (2,1)  

the image R' = (\frac{2}{3}(2)+\frac{1}{3} , \frac{2}{3}(1)-\frac{1}{3} ) or

(\frac{4}{3}+\frac{1}{3} , \frac{2}{3}-\frac{1}{3} )

⇒ R' = (\frac{5}{3} , \frac{1}{3})  

For S = (2, -2) ,

the image S'=  (\frac{2}{3}(2)+\frac{1}{3} , \frac{2}{3}(-2)-\frac{1}{3} ) or

(\frac{4}{3}+\frac{1}{3} , \frac{-4}{3}-\frac{1}{3} )

⇒ S' = (\frac{5}{3} , -\frac{5}{3})

and For T = (-1, -2)

The image T' =  (\frac{2}{3}(-1)+\frac{1}{3} , \frac{2}{3}(-2)-\frac{1}{3} ) or

(\frac{-2}{3}+\frac{1}{3} , \frac{-4}{3}-\frac{1}{3} )

⇒ T' = (\frac{-1}{3} , \frac{-5}{3})

Now, label the image of RST on the graph as shown below in the attachment:

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3 years ago
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3 years ago
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FIND THE SLOPE OF THE LINE
schepotkina [342]

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4/1

Step-by-step explanation:

To get from one dot to the next, you go up by four and to the right by one, making the slope 4/1

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2 years ago
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