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Vadim26 [7]
3 years ago
7

Find the area of each figure. Round to the nearest hundredth if needed.

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0

Answer:

<h3>#1</h3>

<u>Trapezoid</u>

  • A = (b₁ + b₂)h/2
  • A = (4.8 yd + 29.4 ft)(8 yd)/2 = (14.6 yd)(4 yd) = 58.4 yd²
<h3>#2</h3>

<u>Rectangle</u>

  • A = ab
  • A = 2 yd * 3.1 yd = 6.2 yd²
<h3>#3</h3>

<u>Equilateral triangle</u>

  • A = √3/4a²
  • A = √3/4(10²) = 25√3
<h3>#4</h3>

<u>Regular octagon</u>

  • A = aP/2
  • A = 14.5(12*8)/2 = 696

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How do you do this question?
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Step-by-step explanation:

F(x) = ∫ₐˣ t⁷ dt

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At the market, 7 apples cost $4.55. How much do 9 apples cost?
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6 0
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Read 2 more answers
What is the partial fraction decomposition of StartFraction 8 x + 19 Over (x + 8) (x minus 1) EndFraction? StartFraction 3 Over
hoa [83]

The partial fraction decomposition is \frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

<h3>How to determine the decomposition?</h3>

The fraction is given as:

\frac{8x + 19}{(x + 8)(x - 1)}

Split the fraction as follows:

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{A}{x + 8} + \frac{B}{x - 1}

Take the LCM

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{Ax -A + Bx + 8B}{(x + 8)(x -1)}

Cancel the common factors

8x + 19 = Ax - A + Bx + 8B

By comparison, we have:

Ax + Bx = 8x

-A + 8B = 19

This gives

A + B = 8

-A + 8B = 19

Add both equations

9B = 27

Divide by 9

B = 3

Substitute B = 3 in A + B = 8

A + 3 = 8

Solve for A

A = 5

So, we have:

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

Hence, the partial fraction decomposition is \frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

Read more about partial fraction at:

brainly.com/question/12783868

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