3 years ago

Find the area of each figure. Round to the nearest hundredth if needed.

Mathematics

1 answer:

Hitman42 [59]3 years ago

6 0

Answer:

<u>Trapezoid</u>

A = (b₁ + b₂)h/2
A = (4.8 yd + 29.4 ft)(8 yd)/2 = (14.6 yd)(4 yd) = 58.4 yd²

<u>Rectangle</u>

A = ab
A = 2 yd * 3.1 yd = 6.2 yd²

<u>Equilateral triangle</u>

A = √3/4a²
A = √3/4(10²) = 25√3

<u>Regular octagon</u>

A = aP/2
A = 14.5(12*8)/2 = 696

You might be interested in

A student wants to prove that the base angles of an isosceles triangle are congruent. The student draws isosceles triangle ABC w

olga nikolaevna [1]

Answer:

BM=CM bc of the definition of midpoint

AB =AC bc of the def of an isosceles triangle

and angle B = angle D becasur corresponding parts

Step-by-step explanation:

6 0

2 years ago

A monthly contribution of $200 is deposited into an interest-bearing account.If the account has a 4.8% interest rate and compoun

bearhunter [10]

Answer:

22848 is your answer after you subtract the interest rate

Step-by-step explanation:

8 0

3 years ago

Find the value or measure below. Assume that lines that appear tangent to be tangent.

Ahat [919]

Answer:

x = 11.2

Step-by-step explanation:

hypotenuse = 8.4 (radius) + 5.6 = 14

using the Pythagorean theorem:

x² = 14² - 8.4² = 196 - 70.56 =125.44

x = √125.44 = 11.2

5 0

2 years ago

Need help asap !

frutty [35]

The triangle to solve for has a leg or 12 feet, hypotenuse of 20 feet, so solve for Pythagoras $a^{2} + b^{2} = c^{2}$ for a

$a = \sqrt{c^{2} -b^{2}}$

a = 16 feet

5 0

3 years ago

Jessica weighed her dog at the end of each month for three months. At the end of the first month, her dog gained 12.48 pounds. A

uranmaximum [27]

Answer:59.39pounds

Step-by-step explanation:

Because you add 26.34+20.57+12.48 and then you will he 59.39points

6 0

3 years ago