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Paul [167]
3 years ago
11

After having been on the air for more than a decade, Fox's American Idol seemed to be suffering from viewer fatigue. The average

number of viewers from the 2011 season through the 2013 season is approximated by f(t) = 32.744e−0.252t (1 ≤ t ≤ 4) where f(t) is measured in millions, with t = 1 corresponding to the 2011 season.(a) What was the average number of viewers in the 2011 season? million viewers (b) What was the average number of viewers in the 2014 season, assuming that the trend continued into that season? million viewers
Mathematics
1 answer:
mixas84 [53]3 years ago
5 0

Answer:

(a)25.45 million viewers

(b) 11.95 million viewers

Step-by-step explanation:

The average number of viewers from the 2011 season through the 2013 season is approximated by the function:

f(t) = 32.744*e^{-0.252t} (1 ≤ t ≤ 4) where f(t) is measured in millions.

t = 1 corresponds to the 2011 season.

(a) In 2011, t=1

Average number of viewers in the 2011 season,

f(1) = 32.744*e^{-0.252*1}

=25.45 million viewers

(b) In the 2014 season, when =4

f(4) = 32.744*e^{-0.252*4}

=11.95 million viewers

assuming that the trend continued into that season

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We need to use what we know about rectangles to get:

1)

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2) area = 2*W^2 + 24ft*W + 64ft^2

<h3>Working with rectangles:</h3>

We know that rectangles are defined by two measures, width W and length L.

Here we do know that the length of the pool is twice the width, and the width is W, then the length of the pool is:

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This will be equal to the length/width of the pool <u>plus twice the width of the sidewalk</u> (we add it twice because is in both ends) then we have:

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brainly.com/question/17297081

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