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3 years ago

Peter filled 5 cups each with 1 pound of candy. How much candy did the 5 cups contain altogether? 5 1/2 pounds

Mathematics

1 answer:

ollegr [7]3 years ago

4 0

Step-by-step explanation: i think it is B

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How many different four letter alarm codes cam be formed for a house alarm if you can use any uppercase letter in the alaphabet

cricket20 [7]

I believe the answer would be infinite because there are tons of four letter words

7 0

3 years ago

Confused on how to do this, care to help anyone?

ruslelena [56]

Answer:

I would use a proportion for each ingredient:

Cup sugar

4:10=½:x (10×½)÷4= 1,25 cup sugar

Cup brown sugar:

4:10=¼:x (10×¼)÷4= 0.625 cup brown sugar

Peanut butter

4:10=⅔:x (10×⅔)÷4= 1,65 cup peanut butter

Cup oats

2×¼ = ½

4:10=½:x (10×½)÷4= 1,25 cup oats

Cup milk

4:10=¾:x (10×¾)÷4= 1,875 cup milk

Tsp salt

4:10=1:x (10×1)÷4= 2,5 tsp salt

2 tbsp cocoa

4:10=2:x (10×2)÷4= 5 tbsp cocoa

1 tsp vanilla

4:10=1:x (10×1)÷4= 2,5 tsp vanilla

2 eggs

4:10=2:x (10×2)÷4= 5 eggs

3 cups flour

4:10=3:x (10×3)÷4= 7,5 cups flour

12 oz nuts

4:10=12:x (10×12)÷4= 30 oz nuts

8 0

3 years ago

Slove the equation, 5/6x = 15. Show ALL steps!

Likurg_2 [28]

Answer:

x = 18

Step-by-step explanation:

5/6x = 15

Multiply each side by 6/5 to isolate x

6/5 * 5/6 x = 15 *6/5

x = 15/5 *6

x =3*6

x = 18

8 0

3 years ago

Please help me find X

tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

x° = 180° - (102° + 28°) =<em> 50°</em>

5 0

3 years ago

Does anyone know the the answer to the second algebra question? Will give brainiest

astraxan [27]

Answer:

$\sqrt[3]{x^{10} }[\tex]Step-by-step explanation:Exponential Rules:[tex]x^{a} + x^{b} = x^{a + b}$

$\sqrt[b]{x^{a} } =x^{\frac{a}{b} } Original Equation:[tex]\sqrt[3]{x^{10} } = x^{\frac{10}{3} } Answer:[tex]\sqrt[3]{x^{10} }[\tex]Convert the cubed root to a power. Cubed root = [tex]\frac{1}{3}$

$x^{3} x^{\frac{1}{3} }$

Convert them, so they have a common denominator - $\frac{1}{3}$

$\frac{3}{1} * \frac{1}{3}= \frac{9}{3}$

$\frac{9}{3} + \frac{1}{3} = \frac{10}{3}$

[tex]\sqrt[3]{x^{10} }[\tex] = [tex]x^{\frac{10}{3} } [\tex]

8 0

3 years ago