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den301095 [7]
3 years ago
9

0.043118 to 1 significant number

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
8 0

Answer:

0.04.

Step-by-step explanation:

The first significant number is and since the second is 3 we do not change the 4.

mrs_skeptik [129]3 years ago
5 0

Answer:0.04

Step-by-step explanation:numbers from 0-4 can't be rounded up they are rounded off but numbers from 5-9 are rounded up by adding 1 to the number before. Therefore 0.043118 to 1 significant number will be 0.04

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Y-1=-2(x+3) in standard form
romanna [79]

Answer:

2x + y + 5 = 0

Step-by-step explanation:

y − 1 = -2 (x + 3)

y − 1 = -2x − 6

2x + y + 5 = 0

4 0
3 years ago
A box contains 5 plain pencils and 3 pens. A second box contains 4 color pencils and 4 crayons. One item from each box is chosen
LekaFEV [45]

Answer:

3/16

Step-by-step explanation:

3/8 * 4/8= 3/16

3/8= 3 pens out of 8 items

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7 0
4 years ago
Write the equation of the line that is perpendicular to 3x+2y=8 and goes through the point (-5,2)
kifflom [539]

Answer:

\displaystyle y=\frac{2}{3}(x+5)+2

Step-by-step explanation:

We need to find the equation of the line perpendicular to the line 3x+2y=8 and passes through (-5,2).

The given line can be expressed as:

\displaystyle y=-\frac{3}{2}x+4

We can see the slope of this line is m1=-3/2.

The slopes of two perpendicular lines, say m1 and m2, meet the condition:

m_1.m_2=-1

Solving for m2:

\displaystyle m_2=-\frac{1}{m_1}

\displaystyle m_2=-\frac{1}{-\frac{3}{2}}

\displaystyle m_2=\frac{2}{3}

Now we know the slope of the new line, we use the slope-point form of the line:

y=m(x-h)+k

Where m is the slope and (h,k) is the point. Using the provided point (-5,2):

\boxed{\displaystyle y=\frac{2}{3}(x+5)+2}

6 0
4 years ago
How many different combinations are possible if each lock contains the numbers 0 to 39, and each combination contains three dist
Georgia [21]
(e) Each license has the formABcxyz;whereC6=A; Bandx; y; zare pair-wise distinct. There are 26-2=24 possibilities forcand 10;9 and 8 possibilitiesfor each digitx; yandz;respectively, so that there are 241098 dierentlicense plates satisfying the condition of the question.3:A combination lock requires three selections of numbers, each from 1 through39:Suppose that lock is constructed in such a way that no number can be usedtwice in a row, but the same number may occur both rst and third. How manydierent combinations are possible?Solution.We can choose a combination of the formabcwherea; b; carepair-wise distinct and we get 393837 = 54834 combinations or we can choosea combination of typeabawherea6=b:There are 3938 = 1482 combinations.As two types give two disjoint sets of combinations, by addition principle, thenumber of combinations is 54834 + 1482 = 56316:4:(a) How many integers from 1 to 100;000 contain the digit 6 exactly once?(b) How many integers from 1 to 100;000 contain the digit 6 at least once?(a) How many integers from 1 to 100;000 contain two or more occurrencesof the digit 6?Solutions.(a) We identify the integers from 1 through to 100;000 by astring of length 5:(100,000 is the only string of length 6 but it does not contain6:) Also not that the rst digit could be zero but all of the digit cannot be zeroat the same time. As 6 appear exactly once, one of the following cases hold:a= 6 andb; c; d; e6= 6 and so there are 194possibilities.b= 6 anda; c; d; e6= 6;there are 194possibilities. And so on.There are 5 such possibilities and hence there are 594= 32805 such integers.(b) LetU=f1;2;;100;000g:LetAUbe the integers that DO NOTcontain 6:Every number inShas the formabcdeor 100000;where each digitcan take any value in the setf0;1;2;3;4;5;7;8;9gbut all of the digits cannot bezero since 00000 is not allowed. SojAj= 9<span>5</span>
8 0
3 years ago
Use the picture attached!!
evablogger [386]

Answer:

The Correct Answer is C.0.

Hope it hepls you Czn!

Please Mark me as Brainleast!!!!!!!!

5 0
2 years ago
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