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Lapatulllka [165]
3 years ago
13

Solve this i am not able to solve​

Mathematics
1 answer:
Margarita [4]3 years ago
8 0

Answer:

Step-by-step explanation:

First we need to set this ratio up in the coordinate plane. Because this is tangent, the 3 goes opposite the reference angle and the 4 goes along the x-axis, adjacent to the reference angle. We see that we are missing the third side of the triangle when we do this, namely the hypotenuse. We use Pythagorean's Theorem to find that this side is 5. Now we have to deal with the identities for each sin(2A) and cos(2A).

sin(2A) = 2sin(A)cos(A)

We know from the triangle we drew in the coordinate plane that

sin(A)=\frac{3}{5}  and  cos(A)=\frac{4}{5} so we fill in the formula accordingly and then simplify:

sin(2A)=2(\frac{3}{5})(\frac{4}{5})=\frac{24}{25}

cos(2A) has 3 identities; I just picked the one I thought would be easiest to use and went with that one. Regardless of which one you pick you will get the same answer as long as you do the math correctly.

cos(2A)=cos^2(A)-sin^2(A) and filling in the formula:

cos(2A)=(\frac{4}{5})^2-(\frac{3}{5})^2\\cos(2A)=\frac{16}{25}-\frac{9}{25}\\cos(2A)=\frac{7}{25}

I'm not sure why you have 7/2 there...

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3 years ago
The Dade County Fair's admission fee is $8 and each ride costs $2.50. Sonia spent a total of $25.50. How many rides did she go o
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The answer to this question is 7. To solve this, start by subtracting 8 from 25.5, and you get 17.5. This is how much she has spent on rides. Now divide 17.5 by 2.5, and you get 7. I hope this helps!

4 0
3 years ago
An object falls from a position of rest and
kumpel [21]

Answer:

About 4.1323 meters.

Step-by-step explanation:

We can use the following kinematic equations:

\displaystyle v_f  = v_0 + at \text{ and } \Delta d = v_0 t + \frac{1}{2} at^2

We want to determine the distance the object has dropped after falling from rest and reaching an instantenous speed of 9 m/s.

We are given that the acceleration due to gravity is 9.8 m/s².

Using this fact and the first equation, find the time for which it took the object to reach 9 m/s. Note that the initial velocity is 0 m/s since the object started from rest.

\displaystyle \begin{aligned} v_f = v_0 + at \\ \\ (9\text{ m/s}) & = (0\text{ m/s}) + (9.8\text{ m/s$^2$})t \\ \\ 9\text{ m/s} & = (9.8 \text{ m/s$^2$})t \\ \\ t &\approx0.9184 \text{ s} \end{aligned}

To find how far the object dropped, we can use the second equation:

\displaystyle\begin{aligned}  \Delta d & = v_0 t + \frac{1}{2} at^2 \\ \\  & = (0\text{ m/s})(0.9184 \text{ s}) + \frac{1}{2}(9.8 \text{ m/s$^2$})(0.9184 \text{ s})^2 \\ \\ & = 4.1323 \text{ m} \end{aligned}

In conclusion, the object would have dropped about 4.1323 meters.

6 0
3 years ago
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Answer:

The x intercept is (7/5,0)

Step-by-step explanation:

y=−5x+7

To find the x intercept, set y=0 and solve for x

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0-7 = -5x+7-7

-7 = -5x

divide each side by -5

-7/-5 = -5x/-5

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The x intercept is (7/5,0)

3 0
3 years ago
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Answer:

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