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3 years ago

Does anybody know this geometry? (teacher never helped at all)

Mathematics

1 answer:

Ugo [173]3 years ago

5 0

Answer:

3.A: When you want to state that they are congruent.

3.B: When you want to state that their lengths are equal to each other.

3.C: 2nd and 3rd

3.D: Point P, point R, point S.

3.E: PS = 13units

4.A: KL = 35 - 14 = 21 units

4.B: midpoint

4.C: JL = 135/3 = 45 units

Step-by-step explanation:

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The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f

Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

$h(t)=-16t^{2}+25t+5$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

$h(t)=-16(t^{2}-\frac{25}{16}t)+5$

Complete the square

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}$

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}$

Rewrite as perfect squares

$h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

The vertex is the point $(\frac{25}{32},\frac{945}{64})$

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

$0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

$16(t-\frac{25}{32})^{2}=\frac{945}{64}$

$(t-\frac{25}{32})^{2}=\frac{945}{1,024}$

square root both sides

$(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}$

$t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}$

the positive value is

$t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec$

8 0

3 years ago

If quadrangles have all equal angles, are they congruent?

xenn [34]

Answer:

yes because it says all angles are the same

3 0

3 years ago

Eh whats the answer. thankssssssssss

sergey [27]

Answer:

Yea.. Its C

Step-by-step explanation:

7 0

3 years ago

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Algebra 1 help!!!!!!!!!

baherus [9]

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the concept of expo functions.

f(x) = -8(2)^x - 12 ,

for f(0) ,here substitute x = 0

so we get as ,

==> f(0) = -8(2)^0 -12

==> f(0) = -8-12

==> f(0) = -20

hence, f(0) = -20

6 0

3 years ago

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How do you solve 3^2x=81

qwelly [4]

Answer:

x=2

Step-by-step explanation:

3^2x = 81

3^2x = 3^4

Compare powers

2x = 4

x = 2

4 0

3 years ago

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