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3 years ago

15

Find the greatest common factor for the group of numbers. 12 , 28 , 24

1 answer:

irakobra [83]3 years ago

8 0

The greatest common factor, or GCF, is quite self-explanatory. Between two numbers, you have to find the greatest number that can be divided by both numbers without any remainder. This is useful in solving addition and subtraction operations involving fractions. The technique to do this is to place the numbers to the right. Then, place the factors to the left. I'm gonna show the solution so that you can understand better.

4 | 12 28 24
----------------------
| 3 7 6
----------------------

Since all numbers can be divided by 4, you place it on the left side. Then, place the quotients on the next row below. Since, there is no more common factor, it ends with the 2nd row. Then, multiply all the left numbers with the numbers in the very last column.

GCF = 4×3×7×6
GCF = 504

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y=4/5+3 and 3/5

Step-by-step explanation:

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2 years ago

Solve for q. √3q + 2 = √5

34kurt

Answer:

$q = 0.0186$

Step-by-step explanation:

To solve for q, we initially place everything with the term q to one side of the equality, and everything without the term q to the other side of the equality.

So

$\sqrt{3q} + 2 = \sqrt{5}$

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3 years ago

In a local shelter, 300 people donated blood during the blood donation week. The samples collected of the different blood types

Anna007 [38]

Answer:

D)24 people

Step-by-step explanation:

Total number of people, x=300

Number of people donated blood with type A, y

$=\frac{28}{100}\times x\\=\frac{28}{100} \times 300\\=84$

Number of people donated blood with type B, z

$=\frac{20}{100}\times x\\=\frac{20}{100} \times 300\\=60$

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3 years ago

Read 2 more answers

When obtaining a confidence interval for a population mean in the case of a finite population of size N and a sample size n whic

Elanso [62]

Answer:

95% Confidence interval for the mean

$142.8 \leq\mu\leq158.4$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the mean of a finite population.

The error is multiplied by the following finite population correction factor:

$cf=\sqrt{\frac{N-n}{N-1} }$

The standard deviation can be estimated as

$\sigma=\frac{s}{\sqrt{n}} \sqrt{\frac{N-n}{N-1} } =\frac{24.4}{\sqrt{32} }* \sqrt{\frac{200-32}{200-1} }=3.963$

The 95% confidence interval has a z value of 1.96, so it becomes:

$M-z*\sigma_c\leq\mu\leq M+z*\sigma_c\\\\150.6-1.96*3.963\leq\mu\leq 150.6+1.96*3.963\\\\ 142.8 \leq\mu\leq 158.4$

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3 years ago

For f (x) = 9 * 81^x evaluate f(-1/2)

LekaFEV [45]

Step-by-step explanation:

f(x) = 9 * 81^x

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2 years ago