Answer:
Let's define the variables:
M = mother's age
D = daughter's age.
"a mother is twice as old as her daughter"
This can be written as:
M = 2*D
"5 years from now she will be thrice as old as her daughter"
(M + 5) = 3*D
We want to know how old is the mother five years from now.
First, our equations are:
M = 2*D
(M + 5) = 3*D
First, we need to isolate one of the variables in one of the equations, because for the solution we want the mother's age, we should isolate the daughter's age.
Let's isolate D in the first equation:
M/2 = D
Now we can replace this in the other equation:
Now we can replace this on the other equation:
(M + 5) = 3*(M/2)
M + 5 - (3/2)*M = 0
-(1/2)*M + 5 = 0
5 = (1/2)*M
2*5 = M = 10
So the mother is 10 years old (this hasn't a lot of sense, maybe there is a wrong number on the question)
and 5 years from now, the mother will be:
10 + 5 = 15 years old.
Answer:
¼ hours or 15 minutes
Step-by-step explanation:
let the time it will for laura to catch up with Tony be 't'
Distance = speed × time
Distance corvered by Laura in time (t) = Distance corvered by Tony in time (t) + Distance between Tony and Laura
6×t = 4×t + ½
6t = 4t + ½
2t = ½
t = ¼ hours or 15 minutes
<u>B</u><u>R</u><u>A</u><u>I</u><u>N</u><u>L</u><u>I</u><u>E</u><u>S</u><u>T</u><u> </u><u>PLEASE</u>
<h2>
<u>H</u><u>O</u><u>P</u><u>E</u><u> </u><u>I</u><u>T</u><u> </u><u>H</u><u>E</u><u>L</u><u>P</u><u>S</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u>;-)</h2>

<u>Answer</u><u>:</u>
<u>
</u>
<u>Hope </u><u>you</u><u> could</u><u> get</u><u> an</u><u> idea</u><u> from</u><u> here</u><u>.</u>
<u>Doubt</u><u> clarification</u><u> </u><u>-</u><u> </u><u>use </u><u>comment</u><u> section</u><u>.</u>
Answer:
112/17.92 = x, y = 112 + x
Step-by-step explanation:
You have to get x first, then plug in to next equation.