All categories

3 years ago

How much longer is a 12 cm pencil then A 1 dm pen?

2 answers:

8 0

1 dm is equal to 10 cm.
To find the answer, you have to convert the dm to cm.
This would be 10 cm, since 1 dm is 10 cm.
The last thing to do is just subtract 10 from 12 to get the answer.
The pencil is 2 cm longer than the pen.

LenKa [72]3 years ago

4 0

20% or 2 cm 1 dm = 10 cm.

You might be interested in

The coordinates of the vertices of quadrilateral ABCD are A(-5, 1), B(-2,5), C(5, 3),

sladkih [1.3K]

Step-by-step explanation:

To calculate a slope, we need to apply: $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Applying formula to each slope:

$m_{AB}=\frac{5-1}{-2-(-5)} = \frac{4}{3} \\m_{BC}=\frac{3-5}{5-(-2)} =\frac{-2}{7}\\m_{CD}=\frac{-1-3}{2-5}=\frac{-4}{-3} =\frac{4}{3}$

So, as you can see, there are equal pair of slopes, meaning that they are parallels, which demonstrate that it's actually a quadrilateral figure.

6 0

3 years ago

Read 2 more answers

Please help!!!!!!!!!!

Degger [83]

I hope this helps you

4 0

3 years ago

This problem is correct??

ale4655 [162]

yes you are correct evreything is correct

6 0

4 years ago

1-58. Mr. Wright was making a table to figure out how much it costs to send a certain numt

Drupady [299]

A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Given that

$\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]$

Let:

$L \to$ Letters

$C \to$ Cost

Using proportional reasoning, we have:

$C = kL$

Where

$k \to$ ratio of proportion

For the first values of C and L, we have:

$C = kL$

$0.45 = k \times 10$

Divide both sides by 10

$k = 0.045$

So, the equation of proportion is:

$C = 0.045L$

When C = 6.75, we have:

$C = 0.045L$

$6.75 = 0.045L$

Solve for L

$L = \frac{6.75}{0.045}$

$L = 150$

When L = 7, we have:

$C = 0.045L$

$C = 0.045 \times 7$

$C = 0.315$

When L = 1, we have:

$C = 0.045L$

$C = 0.045 \times 1$

$C = 0.045$

When L = 500, we have:

$C =0.045L\\$

$C =0.045 \times 500$

$C =22.5$

When C = 18.90, we have:

$C = 0.045L$

$18.90 = 0.045L$

Solve for L

$L=\frac{18.90}{0.045}$

$L=420$

Hence, the complete table is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$