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Rus_ich [418]
3 years ago
15

Can someone plz help me with this

Mathematics
1 answer:
andrezito [222]3 years ago
8 0

Answer:

I believe the answer is 43.25

Step-by-step explanation:

The sum of all of the angles has to equal 180 degrees. The degree 93.5 is already known so you can subtract that from 180. We have 86.5 left, which is the sum of the two angles that we don’t know yet. I am assuming that they are equal, so you can divide 86.5 by two and get 43.25. I believe this is your answer.

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Select the correct answer.
alexira [117]

Answer:

\huge\boxed{A.\ -\dfrac{9}{4}+2i}

Step-by-step explanation:

The standard form of a complex number:

z=a+bi\\\\a,\ b\in\mathbb{R}

3i+\left(\dfrac{3}{4}+2i\right)-(3+3i)=3i+\dfrac{3}{4}+2i-3-3i\\\\=\left(\dfrac{3}{4}-3\right)+(3+2-3)i=-2\dfrac{1}{4}+2i=-\dfrac{9}{4}+2i

3 0
3 years ago
There are 24 crayons in a box how many boxes will be needed for 16 children if each child gets 8 crayons?
otez555 [7]

Answer:5.33333

Step-by-step explanation:

1 child = 8 crayon

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7 0
3 years ago
Read 2 more answers
What is the probability there are exactly 2 customers in line in a two-server model? selected answer:
svlad2 [7]
Im the answer choice is g.
6 0
4 years ago
Which numbers are rational numbers and irrational numbers and why
slamgirl [31]

Answer:

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6 0
4 years ago
A consumer group surveyed 146 airplane travelers after a flight and found that 132 of them would fly that airline again. Find th
prohojiy [21]

Answer:

\hat p =\frac{X}{n}

And replacing we got:

\hat p =\frac{132}{146}= 0.904

And for this case the standard error assuming normality would be given by:

SE= \sqrt{\frac{\hat p (1-\hat p)}{n}}

And replacing we got:

SE= \sqrt{\frac{0.904*(1-0.904)}{146}}= 0.024

Step-by-step explanation:

For this problem we know the following notation:

n= 146 represent the sample size selected

X= 132 represent the number of airplane travelers who after a flight  would fly that airline again

The estimated proportion for this case would be:

\hat p =\frac{X}{n}

And replacing we got:

\hat p =\frac{132}{146}= 0.904

And for this case the standard error assuming normality would be given by:

SE= \sqrt{\frac{\hat p (1-\hat p)}{n}}

And replacing we got:

SE= \sqrt{\frac{0.904*(1-0.904)}{146}}= 0.024

5 0
3 years ago
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