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3 years ago

Which function is best represented by this graph

Mathematics

2 answers:

wlad13 [49]3 years ago

4 0

Its "Y" for sure locator point is @ (0, 3)

Zolol [24]3 years ago

3 0

J is the correct answer

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Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (

Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

$P(\frac{T}{S}) = 0.95$

$P(\frac{T}{S^c}) = 0.05$

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

$P(S^c) = 1 - P(S)$

= 1 - 0.3

= 0.7

ii. $P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}$

$= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }$

$= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}$

= 0.8906

iii. $P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}$

$= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }$

$= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}$

= 0.0221

We simply applied the above formulas so that the each part could come

8 0

2 years ago

What is 4387 times 9 solved out

tamaranim1 [39]

Answer:

4387 x 9 = 39,483

Step-by-step explanation:

Please consider giving me Brainliest

darrylh3333

Hope this helps

8 0

3 years ago

Find g^−1 (x) when g(x) = 3/5 x −9. 5/3x − 1/9 5/3 x + 9 −3/5 x+ 9 5/3 x + 15

Cerrena [4.2K]

Answer:

5/3 x + 15

Step-by-step explanation:

The inverse of a function is the reflection across the line y = x. As such, algebraically it is found by switching y and x in the equation and isolating to solve for y.

g(x) = 3/5 x - 9

x = 3/5 y - 9

x + 9 = 3/5 y

5(x+9) = 3y

(5x + 45)/3 = y

5/3x + 15 = y

8 0

3 years ago

The sum of 1/11 and 1/15 is closest to 0 1 or 2

vova2212 [387]

It is closer 1/11 is closer to 2 and 01 because it's smaller , 1/15 is also close but not as close

3 0

3 years ago

Simplify the expression where possible. (6^3)^-3

astraxan [27]

$\bf ~\hspace{7em}\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
~\hspace{4.5em}
a^n\implies \cfrac{1}{a^{-n}}
~\hspace{4.5em}
\cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
(6^3)^{-3}\implies 6^{-3\cdot 3}\implies 6^{-9}\implies \cfrac{1}{6^9}\implies \cfrac{1}{10077696}$

3 0

3 years ago

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