Answer:
C. From 0 to 4000 choose Old Process, From 4000 to infinity choose New Process
Explanation:
Let the number of raft be denoted by Y
We are told that old process requires an investment of $4,000 and a variable cost of $6 per raft
Thus, old process cost is;
C_old = 4000 + 6Y
We are told that the new process has an investment of $20,000 and that the variable cost is $2 per raft..
Thus, new process cost is;
C_new = 20000 + 2Y
To find the volume demand by which each process will be chosen, we will equate both old and new costs to get;
4000 + 6Y = 20000 + 2Y
Rearranging, we have;
6Y - 2Y = 20000 - 4000
4Y = 16000
Y = 16000/4
Y = 4000
Thus, old process should be applied from 0 to 4000 and new process should be applied from 4000 to infinity.
Thus, option C is correct.
The machine's second year depreciation expense is $3,200.
Depreciation is a method that is used to expense the cost of an asset. The units-of-production depreciation method determines the depreciation expense based on the units of goods that the machine produces in a given year.
Unit of production depreciation expense = (unit of goods produced in year 2 / total units the machine can produce) x (cost of the asset - salvage value)
Total units the machine can produce = 1500 + 1250 + 1000 = 3750
(1000 / 3750) x ($15,000 - $3,000) = $3,200
A similar question was answered here: brainly.com/question/15858628?referrer=searchResults
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