Question

Suppose a game uses a spinner with five equal sections numbered 1–5 to determine the value of tokens given to the player spinning it. what is the expected value of the number of tokens?

Answer 1

Answer with explanation:

Number of sections on the spinner=5={Marked as ,1,2,3,4,5}

When the spinner is Spun once

Probability of getting any of 1,2,3,4, and 5

          $=\frac{1}{5}$

As, it is not given, that if a player spun a Spinner and get, either of,1,2,3,4,or.5, on each section how many token someone is getting.

Suppose player landing on section 1 is getting token=1, Player landing on section 2 is getting token =2,..............

So, Expected value can be Calculated by,the following method

E(x)=x × P(x)

 $=1 \times \frac{1}{5} +2 \times \frac{1}{5} +3 \times \frac{1}{5} +4 \times \frac{1}{5} +5 \times \frac{1}{5} \\\\=(1+2+3+4+5) \times \frac{1}{5}\\\\=15 \times\frac{1}{5}\\\\=3$  

Answer 2

5 because they would most likely want a high amount of coins it's common sense. But if they were very strategic they'd probably also pick 3 but most of the time the value expected would be 5.