Answer:
$17.70
Step-by-step explanation:
$15.00×18%=$2.70
$15.00+$2.70=$17.70
Answer:
-56x^9+24x^8
Step-by-step explanation:
Answer:
We have a + b as;
2 + 3 = 5
Step-by-step explanation:
Here, we want go get the value of a and b
from the second equation, we can get an expression for b
We have this as;
7a - b = 11
Thus,
b = 7a - 11
Now, from here, we can substitute the value of b into the first equation
We have this as;
5a + 4(7a - 11) = 22
5a + 28a -44 = 22
33a = 22 + 44
33a = 66
a = 66/33
a = 2
Recall;
b = 7a - 11
substituting the value of a from above;
b = 7(2) - 11
b = 14 - 11
b = 3
-x - y = -5
y = x + 1
-x -(x + 1) = -5
-x - x - 1 = -5
-2x = -5 + 1
-2x = -4
x = -4/-2
x = 2
y = x + 1
y = 2 + 1
y = 3
solution is : (2,3)
We will get the number of possible selections, and then subtract the number less than 25 cents.
We can choose the number of dimes 5 ways 0,1,2,3 or 4.
We can choose the number of nickels 4 ways 0,1,2 or 3.
We can choose the number of quarters 3 ways 0,1, or 2.
That's 5*4*3 = 60 selections
Now we must subtract from the 60 the number of selections of coins that are less than 25 cents. These will involve only dimes and nickels.
To get a selection of coin worth less than 25 cents:
If we use no dimes, we can use 0,1,2 on all 3 nickels.
That's 4 selections less than 25 cents. (that includes the choice of No coins at all in the 60, which we must subtract).
If we use exactly 1 dime , we can use 0,1,2, or all 3 nickels.
That's the 3 combinations less than 25 cents.
And there is 1 other selection less than 25 cents, 2 dimes and no nickels.
So that's 4+3+1 = 8 selections which we must subtract from the 60.
Answer 60-8 = 52 selections of coins worth 25 cents or more.
