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Lena [83]
2 years ago
6

What is the volume of a cylinder with a diameter of 20 meters and a height of 4 meters?

Mathematics
2 answers:
IgorLugansk [536]2 years ago
7 0

Answer: 1256.64

Step-by-step explanation:

It was easy but if you need help and its this knid of problem look up.

Aleks [24]2 years ago
4 0

Answer:

1256.64 cubic meters

Step-by-step explanation:

You might be interested in
(6, - 3, 1) and (8,9,-11) find the angle between the vector​
Svetllana [295]

Answer:

The angle between the two vectors is 84.813°.

Step-by-step explanation:

Statement is incomplete. Complete form is presented below:

<em>Let be (6,-3, 1) and (8, 9, -11) vector with same origin. Find the angle between the two vectors. </em>

Let \vec u = \langle 6, -3, 1 \rangle and \vec v = \langle 8,9,-11 \rangle, the angle between the two vectors is determined from definition of dot product:

\theta = \cos^{-1} \left(\frac{\vec u \,\bullet \,\vec v}{\|\vec u\|\cdot \|\vec v\|} \right) (1)

Where:

\vec u, \vec v - Vectors.

\|\vec u\|, \|\vec v\| - Norms of each vector.

Note: The norm of a vector in rectangular form can be determined by either the Pythagorean Theorem or definition of Dot Product.

If we know that \vec u = \langle 6,-3,1 \rangle and \vec v = \langle 8, 9,-11 \rangle, then the angle between the two vectors is:

\theta = \cos^{-1}\left[\frac{(6)\cdot (8) + (-3)\cdot (9) + (1)\cdot (-11)}{\sqrt{6^{2}+(-3)^{2}+1^{2}}\cdot \sqrt{8^{2}+9^{2}+(-11)^{2}}} \right]

\theta \approx 84.813^{\circ}

The angle between the two vectors is 84.813°.

6 0
2 years ago
1. 81 1/2 x 27 1/3 <br><br> 2. 32x = 729
stepan [7]

Answer:

1.

Step-by-step explanation:

1. 1.811/2=3.622 271/3=813

3.622*813=2,944.686

this is number one

2. 32x=729

divide both sides by 32

32x=729/32=

22.78125 approximate=22.8 or 23

3 0
2 years ago
Find the volume of the prism 8 units 2 units 5 units
lesantik [10]

Answer:

80 units cubed

Step-by-step explanation:

Volume=Base area x Height=16x5=80

Base area=8x2=16

Height=5

5 0
2 years ago
Im new to this, and feeling hopeless '-'
Ede4ka [16]
\left[\begin{array}{ccc}22&18\end{array}\right]\times\left[\begin{array}{cccc}5&18&32&40\\25&40&38&12\end{array}\right]\\\\=\left[\begin{array}{cccc}22\cdot5+18\cdot25&22\cdot18+18\cdot40&22\cdot32+18\cdot38&22\cdot40+18\cdot12\end{array}\right]\\\\=\left[\begin{array}{cccc}560&1116&1388&1096\end{array}\right]

second question:

January: 32 · 22 + 38 · 18 = 704 + 684 = 1388

December: 18 · 22 + 40 · 18 = 396 + 720 = 1116

1388 - 1116 = 272

Answer: $272.
7 0
3 years ago
If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)
Lelu [443]
Hello : 
<span>If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)
</span>(f+g)(x)= f(x) +g(x) = x/2-2  +2x²+x-3 = x/2 +2x²+x-5
(f+g)(x)= (x+4x²-2x-10) /2
(f+g)(x)= (4x²+3x-10)/2 = 2x²+3/2 x -5
4 0
3 years ago
Read 2 more answers
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