A) Probability that at least one of these golfers makes a hole in one on the 10th hole at the same tournament is
<span>=1−(<span>2493/2494</span><span>)^<span>5
=1-(0.99)^5
= 1- 0.96
=0.4
b) T</span></span></span><span>he probability that all of these golfers make a hole-in-one on the 10th hole at the same tournament
=</span>(<span>1/2494</span><span>)<span>5
</span></span>
which is nearly zero.
That would be 25 units. You can draw it out and you would get 25 units, or you could see the difference in -10 and 15, their distance would be 25 units.
That made no sense.
Step-by-step explanation:
-4,-3,-2,-1,4. that's the answer
Answer: -13, -17, -21
Explanation: Subtract 4 from each term. Do this for 3 terms
