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mars1129 [50]
2 years ago
9

Solve the equation below. 2/3 (9x - 12) - 6x

Mathematics
2 answers:
SVEN [57.7K]2 years ago
6 0

Answer:

-8

Step-by-step explanation:

1. Simplify

2/3 (9x - 12) -6x —-> 2 (9x - 12) -6x/3

2. Distribute

2(9−12)/3 -6x

18x - 24/3 -6x

3. Find common denominator

18 −24/3 + 3(-6)x/3

4. Combine fractions with common denominator

18−24+3(−6)/3

5. Multiply the numbers

18−24+3(−6)/3 ——> 18−24−18/3

6. Combine like terms

18−24−18/3 ——> -24/3

7. Cancel terms that are in both the numerator and denominator

−24/3

−8

Hope it helps! Have a great day! :D

beks73 [17]2 years ago
3 0

48

Step-by-step explanation:

idek I just need tge points so don't put what I put

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If r = 5 units and x = 11 units, then what is the total surface area of the cylinder shown above?
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Answer: 502.65

Step-by-step explanation: A= 2πrh + 2πr^ this is the formula for solving the surface area so now you must substitute

2·π·5·11+2·π·5^

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add and you will get 502.65 hope this helps mark me brainliest if it did

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2x^2+3x-2, a=0 How do I find the derivative?
Ghella [55]

You can use the definition:

\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h

Then if

f(x) = 2x^2+3x-2

we have

f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2

Then the derivative is

\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}

I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is

f'(0) = 4(0) + 3 = 3

and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-2) = 3 (<em>x</em> - 0)

<em>y</em> + 2 = 3<em>x</em>

<em>y</em> = 3<em>x</em> - 2

5 0
3 years ago
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