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Rashid [163]
4 years ago
9

Use the Pythagorean theorem to find the distance from A(5, -3) to B(6, 0).

Mathematics
1 answer:
Rzqust [24]4 years ago
3 0

Answer:

<h3>The distance from A to B is 7 units.</h3>

Step-by-step explanation:

Given:

A(5, -3) and B(6, 0).

So, to find the distance using Pythagorean theorem.

Plot the given points on a graph as shown below.

Now, we construct a right angled triangle ABC such that C is (6,-3)

Now, from the graph, AC = 1 units, BC = 3 unit

Applying Pythagorean theorem on triangle ABC:

AB^{2}= BC^{2}+AC^{2}

⇒AB^{2}=3^{2}+1^{2}

⇒AB^{2}=9+1

using square root both the sides

⇒AB=10

⇒AB=3.16.

AB=3.16 units.

Therefore, the distance from A to B is 3 units(approximately).

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What is the slope of this line?<br> y = 7x - 5<br> Slope = [?]<br> Enter
weqwewe [10]

Answer:

the slope of this line is 7.

Step-by-step explanation:

I hope this helps

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3 years ago
Identify the pair of angles shown in the figure. answers A. LINEAR PAIR B. COMPLEMENTARY C. CONGRUENT D. VERTICAL
posledela

Answer:

linear pair

Step-by-step explanation:

The two angles add together to form a straight line, which is 180 degrees.

These angles are supplementary, or a linear pair

4 0
3 years ago
Read 2 more answers
Help me I beg u! The pre-image coordinates of a triangle are J(-6,9), K(-6,4), and L(-3,4). The coordinates of the transformed t
Elena-2011 [213]

Answer:

A. Translation

Step-by-step explanation:

Given

Preimage

J = (-6,9)

K = (-6,4)

L = (-3,4)

Image

J' = (2,9)

K' = (2,4)

L' = (5,4)

Required

Which transformation occurred

The transformation that occurs is translation because each of the preimage were translated or shifter right by 8 units.

The rule applied here is:

(x,y)=>(x+8,y)

So, we have:

J = (-6,9) ==> (-6+8,9) = (2,9)

K = (-6,4) ==> (-6+8,4) = (2,4)

L = (-3,4) ==> (-3+8,4) = (5,4)

<em>Hence, the transformation is (a) Translation</em>

4 0
3 years ago
The sales tax in your city is 4.4%, and an item cost $3 before tax
adoni [48]

Answer:

after tax is added the price would be 3.13$

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Find the value of the expression (-101)+102+(-103)+104+...+(-199)+200. (with steps)
Juliette [100K]
 hello : 
<span>(-101)+102+(-103)+104+...+(-199)+200
=(  </span>(-101)+(-103) +....+ (-199) ) +( (102) + ( 104) +....+(200))
let : A = (  (-101)+(-103) +....+ (-199) )
       B = ( (102) + ( 104) +....+(200))
note : the sum n term of arithemtic sequence 
S= n/2(u1 + un)
 un = u1 +(n-1) d       u1 : the first term      d : the common diference
in A :  u1= -101      d = -2       n = 49... 
in B : u1 =102       d=2        n= 49
A = 49/2(-101-199) =-7350
B=49/2(102+200)=4949
(-101)+102+(-103)+104+...+(-199)+200 = A+B =-2401
5 0
3 years ago
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