All categories

4 years ago

What is the value of x when f(x)=-4

Mathematics

1 answer:

HACTEHA [7]4 years ago

8 0

How do you even do this i think it’s 8

You might be interested in

F(x)=-5x-7 g(x)=6x-4<br><br> Find F(x)+g(x)<br><br> Please show steps

olga_2 [115]

Answer:

hi!

So it gives you what f(x) equals AND what g(x) equals.

So, if you want F(x)+g(x), then just fill it in!

So it would be

-5x - 7 +6x - 4

-5x+5x-7+6x+5x-4

-7+11x-4

-7 + 7 +11x - 4+7

So, your answer would be 11x + 3

Hope i helped!

5 0

3 years ago

Hey help help pls help quick help

Rufina [12.5K]

Answer:

Step-by-step explanation

you see 6 squrs and One whole.

4 0

3 years ago

Read 2 more answers

What are the x-intercepts of the parabola x2 + 4x −12?

vladimir1956 [14]

When you factor the parabola you get
(x+6)(x-2)
set each of these equal to zero
x+6=0 x-2=0
solve for x
x=-6 x=2
these are your x-intercepts
(-6,0) and (2,0)

6 0

3 years ago

A company is holding a sales contest for its sales reps. 12 sales reps are based in Office A and 7 sales reps are based in Offic

NikAS [45]

Answer:

55,440 ways

Step-by-step explanation:

In this situation, since the bonuses are different, the order of the sales reps receiveing the bonus matters, thus permutations should be used.

The number of ways to pay the bonuses in office A (pick 3 out of 12) is:

$A=\frac{12!}{(12-3)!} =12*11*10 = 1,320\ ways$

The number of ways to pay the bonuses in office B (pick 2 out of 7) is:

$B=\frac{7!}{(7-2)!} =7*6 =42\ ways$

Considering both offices, the number of ways to pay out the bonuses is:

$N= A*B = 1320*42\\N=55,440\ ways$

3 0

4 years ago

Eric needs 1/2 deck of playing cards for a magic trick. He only has 2/7 of a deck. What fraction of a deck does Eric still need?

tatyana61 [14]

Answer: Eric still needs $\frac{3}{14}$ of a deck.

Step-by-step explanation:

You know that:

- Eric need 1/2 deck of playing cards.

- Eric has 2/7 of a deck.

Therefore, to find the fraction of a deck that Eric still needs, you must subtract 1/2 and 2/7:

- Find the least common multiple of the denominators:

$2=2*1\\7=7*1$

$LCM=2*7*1=14$

- Now, you can make the subtraction:

$\frac{(7*1)-(2*2)}{14}=\frac{7-4}{14}=\frac{3}{14}$

Therefore, he still needs $\frac{3}{14}$ of a deck.

4 0

3 years ago