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polet [3.4K]
3 years ago
9

Hey help help pls help quick help

Mathematics
2 answers:
Rufina [12.5K]3 years ago
4 0

Answer:

D

Step-by-step explanation

you see 6 squrs and One whole.

Kitty [74]3 years ago
4 0

Answer: D

Step-by-step explanation: since its not asking for the answer if you look at both fractions are separated on the model and on the left is 1/6 and then on the right is 1/2 and if your looking for the answer its 3! Hope this helps!

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Which expression is NOT equivalent to 24?<br><br> 2x2x2x3<br> 2x2x6<br> 2x2x3x3<br> 2x4x3
professor190 [17]

Answer:

2x2x3x3=36...so it is not equivalent to 24

5 0
3 years ago
Read 2 more answers
I really need help on my question
Nitella [24]

Answer:

D

Step-by-step explanation:

-1.25 is less than -1.02 and 1.4.

> -1.25 + 1.02 = -0.23

1.4 is a greater amount because it is a positive number

So, if you put it this way, -1.25 is lesser, -1.02 is the 2nd least, & 1.4 is the greatest.

Which means your overall answer should be -1.25 < -1.02 < 1.4

5 0
3 years ago
25 + 18-6-1............​
ch4aika [34]

Answer: 36

Step-by-step explanation:

25 + 18 - 6 - 1

25 + 18 = 43

43 - 6 - 1

43 - 6 = 37

37 - 1 = 36

7 0
3 years ago
Read 2 more answers
Limit as x approaches 0 of (sin^2x)/x
melisa1 [442]

Answer:

<h3>0</h3>

Step-by-step explanation:

Given the expression

\lim_{x \to \ 0} \frac{sin^2x}{x}

Substitute the value of x in the function

= \frac{sin ^2(0)}{0}\\= 0/0 (indeterminate) \\

Apply l'hospital rule

\lim_{x \to \ 0} \frac{d/dx(sin^2x)}{d/dx(x)}  \\=  \lim_{x \to \ 0} \frac{(2sinxcosx)}{1}  \\

Substitute the value of x

= 2 sin(0)cos(0)

= 2 * 0 * 1

= 0

Hence the limit of the function is 0

5 0
3 years ago
The graph of f(x) is shown.what is the value of x when f(x)=4
Dmitry [639]

Answer:

X=3

Step-by-step explanation:

5 0
3 years ago
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