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3 years ago

Help ASAP please

Mathematics

1 answer:

Neko [114]3 years ago

7 0

C. Is the best answer

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Given that the mass of an average linebacker at Ursinus College is 250 lbs and the radius of a pea is 0.50 cm, calculate the num

Brilliant_brown [7]

Answer:

1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle

Step-by-step explanation:

Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is

V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³

the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)

The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be

ρ= m/V

since both should be equal ρ=ρa , then

ρa= m/V =N*L/V → N =ρa*V/L

replacing values

N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers

N=1.544*10⁹ Linebackers

7 0

3 years ago

What is the value of the expression 14 + 6 • 2 – 10 ÷ 5?

Alex777 [14]

D 24 do order of operations perenthesis, exponents, multiplication or division, addition or subtraction

7 0

3 years ago

Please help me <br> I will give brainlist please explain

Airida [17]

So you have to graph that on to the chart i think

3 0

3 years ago

Quadrilateral EFGH with diagonals EG and HF must be a parallelogram if (1) EF FG  and GH HE  (2) EG FH  (3) EG FH  (4) EF HG

qwelly [4]

Answer:

EF = HG and EF || HG

Step-by-step explanation:

A quadrilateral is a polygon shape with four sides and four angles.

A parallelogram is a quadrilateral with two pairs of parallel sides. The following are properties of a parallelogram:

Opposite sides are equal and parallel.
Opposite angles are equal to each other.
Consecutive angles are supplementary
The diagonals of a parallelogram bisect each other.

If Quadrilateral EFGH with diagonals EG and HF is a parallelogram then EF = HG and EF || HG

5 0

3 years ago

Simplify x²-49/3x+21

Vera_Pavlovna [14]

First, you factor and simplify (respectively) the numerator and denominator. Your equation becomes:

$\frac{(x-7)(x+7)}{3(x + 7)}$

Notice, there is a (x + 7) on both the top and the bottom. Because of this, they cancel each other out. What is left is your answer:

$\frac{(x-7)}{3}$

3 0

3 years ago

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