area=legnth times width
we notice this is a special case
(a+b)(a-b)=a^2-b^2
area=(a+3b)(a-3b)=a^2-9b^2
area=a^2-9b^2
Answer:
33600 m²
Step-by-step explanation:
The top and bottom horizontal sides are parallel, so this is a trapezoid with bases DC and AB. The height is BC.
area of trapezoid = (a + b)h/2
where a and b are the lengths of the bases, and h is the height.
We need to find the height, BC.
Drop a perpendicular from point A to segment DC. Call the point of intersection E. E is a point on segment DC.
DE + EC = DC
EC = AB = 360 m
DC = 600 m
DE + 360 m = 600 m
DE = 240 m
Use right triangle ADE to find AE. Then BC = AE.
DE² + AE² = AD²
DE² + 240² = 250²
DE² = 62500 - 57600
DE² = 4900
DE = √4900
DE = 70
BC = 70 = h
area = (a + b)h/2
area = (600 m + 360 m)(70 m)/2
area = 33600 m²
We have a system of equations in two variables, namely, a and c. Use the substitution to find a and c.
I think division, at least that's how I wrote it in school
