Find the answer in simplest form. 33/4 divided by 17/6=

A physician wants to develop criteria for determining whether a patient's pulse rate is atypical, and she wants to determine whe

valkas [14]

Answer:

a) 66.1 < μ < 82.7

b) 71.9 < μ < 97.7

c) D. No, because the two confidence intervals overlap, we cannot conclude that the two population means are different.

Step-by-step explanation:

Confidence interval is given by the formula

M±t×( $\frac{s}{\sqrt{N} }$ ) where

M is the sample mean
t is the corresponding t value for 95 confidence level
s is the sample standard deviation
N is the sample size

a. Construct a 95% confidence interval estimate of the mean pulse rate for males.

For men:

M=74.4 t=2.262 s=11.6207 N=10 then confidence interval is:

74.4±2.262×( $\frac{11.6207}{\sqrt{10 } }$ ) ≈ 74.4±8.3

b. Construct a 95% confidence interval estimate of the mean pulse rate for females.

For women:

M=84.8 t=2.262 s=18.0488 N=10 then confidence interval is:

84.8±2.262×( $\frac{18.0488 }{\sqrt{10 } }$ ) ≈ 84.8±12.9

c. Compare the preceding results. Can we conclude that the population means for males and females are different?

Difference of Population means for males and females are not statistically significant, since confidence intervals overlap.

4 0

3 years ago

Subtract polynomials. (9x²+ 3x – 11) - (2x²+ 4x + 3)

Stella [2.4K]

Answer:

7x^2-x-14

Step-by-step explanation:

7 0

3 years ago

A rope is cut into three pleces. The lengths are given as 2ab(a - b), 3^2(a + 2b), and b^2 (2a - b).

gladu [14]

Answer:

Step-by-step explanation:

Hello, please consider the following.

$2ab(a-b)+3a^2(a+2b)+b^2(2a-b)\\\\=2a^2b-2ab^2+3a^3+6a^2b+2ab^2-b^3\\\\=\boxed{3a^3-b^3+8a^2b}$

For a = 2, b = 3 the total is

$3\cdot 2^3-3^3+8\cdot 2^2 \cdot 3\\\\=3*8-27+96\\\\=24-27+96\\\\=\boxed{93}$

Thank you

6 0

3 years ago

Read 2 more answers

A hummingbird has a wing beat of about 200 beats per second how many wing beats would a hummingbird have in 3 minutes

Hitman42 [59]

36000 wing beats with in 3 min ........as.d.as.df.as.df.as.dfa

4 0

3 years ago

Read 2 more answers

Suppose you want to count the number of four-letter passwords that can be formed using the letters in the word NUMBER. The four

WITCHER [35]

Answer:

D.The password must not follow order matter

Step-by-step explanation:

We are given that suppose you want to count the number of four letters password that can be formed using the letters in the word NUMBER.

We are given that all letters in the password must be all different .There is no nothing saying about order so we can make combination without order .

We have to find the number of 4- letter password that can be formed using letters in the word NUMBER.

By using Permutation formula we find the number of 4- letters password that can be formed by using the letters N,M,B,U,E,R.

Permutation formula : The number of arrangements when taken r objects at a time out of n objects

= $\frac{n!}{(n-r)!}$

Total letters in word NUMBER=N,U,M,B,E,R=6

n=6,r=4

Therefore, the number of arrangements can be made from 6 letters when 4 letters taken at a time = $\frac{6!}{(6-4)!}$

The number of selection can be made from 6 letters when 4 letters taken at a time = $\frac{6!}{(6-4)!}$

The number of selection can be made from 6 letters when 4 letters taken at a time = $\frac{6\times5\times 4\times3 \times 2!}{ 2!}$

$n!=n(n-1)(n-2)(n-3)...........3\cdot.2\cdot.1$

The number of selection can be made from 6 letters when 4 letters taken at a time =360

Option D is correct.

Answer : D.The password must not follow order matter

6 0

3 years ago