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Gala2k [10]
3 years ago
10

HELPP PLEASE I WILL CROWN YOU!!!!! (Solve for X) Please make sure it correct Thank you

Mathematics
1 answer:
andrew-mc [135]3 years ago
6 0

Answer:

x=9

Step-by-step explanation:

These two angles are equal because they are corresponding angles and the two lines are parallel.

13x-7 = 11x+11

Subtract 11x from each side

13x-11x -7 = 11x-11x+11

2x-7 = 11

Add 7 to each side

2x-7+7 = 11+7

2x = 18

Divide each side by 2

2x/2 = 18/2

x =9

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The Math Counts Club had a party at their school. There were 20 cookies and 40 slices of pizza to be shared equally. Each studen
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Answer:

  • 2, 4, 10 or 20 students

Step-by-step explanation:

<u>Prime factors:</u>

  • 20 = 2*2*5
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<u>Common factors of the two numbers: </u>

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Possible number of students as above

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Answer:

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Step-by-step explanation:

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The weight of turkeys is normally distributed with a mean of 22 pounds and a standard deviation of 5 pounds. a. Find the probabi
Masja [62]

Answer:

a. 0.443

b. 0.023

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The weight of turkeys is normally distributed with a mean of 22 pounds and a standard deviation of 5 pounds.

This means that \mu = 22, \sigma = 5

a. Find the probability that a randomly selected turkey weighs between 20 and 26 pounds.

This is the pvalue of Z when X = 26 subtracted by the pvalue of Z when X = 20. So

X = 26

Z = \frac{X - \mu}{\sigma}

Z = \frac{26 - 22}{5}

Z = 0.8

Z = 0.8 has a pvalue of 0.788

X = 20

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 22}{5}

Z = -0.4

Z = -0.4 has a pvalue of 0.345

0.788 - 0.345 = 0.443

The answer is 0.443

b. Find the probability that a randomly selected turkey weighs below 12 pounds.

This is the pvalue of Z when X = 12. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{12 - 22}{5}

Z = -2

Z = -2 has a pvalue of 0.023

The answer is 0.023.

8 0
3 years ago
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