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3 years ago

Which set of ordered pairs represents a function, and how does it represent that function?

1 answer:

5 0

B is the only one thats a function because it has one X for every Y while the other options have multiple X's for one Y. That does not pass the vertical line test and therfore not a function.

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In my town, gas prices are always listed to the thousandths place. Since the smallest coin we have is

Virty [35]

Answer:

It would be rounded to $5.90 per gallon. As if something is 5 or above you round up and if it is 4 or less you round down.

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3 years ago

ASAP PLS

Wittaler [7]

Assuming Earth's gravity, the formula for the flight of the particle is:

s(t) = -16t^2 + vt + s = -16t^2 + 144t + 160.

This has a maximum when t = -b/(2a) = -144/[2(-16)] = -144/(-32) = 9/2.

Therefore, the maximum height is s(9/2) = -16(9/2)^2 + 144(9/2) + 160 = 484 feet.

8 0

3 years ago

Read 2 more answers

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, MOE = 0.04.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601$

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, MOE = 0.02.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401$

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

8 0

3 years ago

Ifa team of three workers each making the us federal minimum wage 7.25 produce 12 rugs what would be total labor cost

Schach [20]

Probably $87 based on the information I was given.

3 0

3 years ago

Each side of a regular polygon is 2.5 cm in length .The perimeter of the polygon is 12.5 cm .How many sides does the polygon hav

Rainbow [258]

Answer:

There are 5 sides in the polygon.

Total perimeter of the polygon is 12.5 cm and it is a regular polygon.

Each side of the polygon is 2.5 cm.

So total number of sides is: Total perimeter of the polygon / Length of each side = 12.5 cm/ 2.5 cm = 5

Hence, the polygon has 5 sides and it is a regular pentagon.

Step-by-step explanation:

I hope this is correct, if it isn't please feel free to let me know and I will fix it. I'm sorry in advance if it is incorrect.

6 0

3 years ago