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Gnesinka [82]
3 years ago
15

PLEASE HELP ME WITH THIS QUESTION. ITS URGUENT

Mathematics
1 answer:
balu736 [363]3 years ago
6 0

Answer:they're both the same size if you put them both in a line

Step-by-step explanation:because each one has four balls in each container so they the same size

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What is 10% of a number whose square<br> is 81
andrezito [222]

Answer: 0.9

Step-by-step explanation:

<u>Let x be the number</u>

<u>Determine the value of the number</u>

x² = 81

√x² = √81

x = 9

<u>Find the 10% of the number</u>

Final number = rate of percentage × original number

Final number = 10% × 9

Final number = \boxed{0.9}

Hope this helps!! :)

Please let me know if you have any questions

5 0
3 years ago
A student creates a table of the equation y = 5x + 8. The student begins the table as shown below. Which shows the correct headi
SVEN [57.7K]

Answer:

1

Step-by-step explanation:

Column A=X the first value for x is 1

Column B has the x value replaced in the equation 5x+8. 5(1) + 8

Column C has the result, y=13

3 0
3 years ago
34 POINTS - LOGICAL ANSWERS
Alecsey [184]
These are the answer that I got:

A. <span>That means: "The more it costs, the fewer people you can invite."

B. <span>Amount you can spend = M; You will have to come up with this number -   whatever you think is reasonable.
</span>
C. (C = Cost per person, P = number of people you can invite )

D. You will have two equations. In the first equation, C will be the per-person cost at the first bowling alley. In the second equation, C will be the per-person cost at the second bowling alley.

E. <span>Be sure to think this through. Yes, you will be able to host more guests at the bowling alley with the lowest per-person cost, but is that the only factor you need to consider? What about location? Quality of lanes and bowling equipment? Music? Food? Customer Service? Consider ALL aspects.</span>  You might pick the more expensive bowling alley because you feel would have a better experience, or maybe you don't want to invite lots of people anyway.<span> 

Hope this helps!</span>

</span>
4 0
3 years ago
How do I solve for a, b and c?
Naya [18.7K]
Firstly expand (x - 3)(ax^2 + bx + c):
ax^3 + bx^2 + cx - 3ax^2 - 3bx - 3c

Now rearrange it so that it's in the form ax^3 + bx^2 + cx + d:
ax^3 + (b-3a)x^2 + (c-3b)x - 3c

Now we can compare both equations:
ax^3 + (b-3a)x^2 + (c-3b)x - 3c = 2x^3 - x^2 - 19x + 12

We get:
(1) a = 2
(2) b - 3a = -1
(3) c - 3b = -19
(4) -3c = 12

If we substitute (1) into (2) we get:
b - 3*2 = -1
b - 6 = -1
b = 5

Now if we solve (4) we get:
-3c = 12
c = -4

Therefor a = 2, b = 5 and c = -4
8 0
3 years ago
Find the Area of the Shaded Region.
Sedbober [7]

Answer:

A of the shaded figure is 90cm

4 0
3 years ago
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