Answer:
y=2x+5 is the answer ALSO CAN WE TALK ABOUT THE FACT THAT MOO975 IS ON THREE QUESTIONS AT THE SAME TIME
Step-by-step explanation:
Answer:
Option C is the correct choice that is 
Step-by-step explanation:
As this is a multiple choice question we will reduce the options and work on it with the given points 
Note:We know that
where there is
sign associated with it have a straight line graph there is no breaking in the line.
And when there is simply
we have a dashed line when we plot it on a graph.
So option B and D are discarded.
Now one-by one we will put the values
to know which equation it satisfies.
If we put
then
.
So working with option A.

Plugging the values.

And we know that
must be equal to
so this is not the right answer.
We are left with only one choice that is C .
So option C is the correct option of the above inequality.
Let

, so that

is the digits in the tens place and

is the digit in the ones place. (Clearly

.)

There are five possible two digits integers that satisfy this relation:





But the first, third, and fifth candidates are even, so they are not prime. The remaining are prime, however, so

or

.
I) HCF - use the smallest powers of each common factors
HCF (A,B) = 2^2 × 3^4 × 5^2
LCM - use the highest powers of each factors
LCM (A,B) = 2^4 × 3^6 × 5^2 × 7^2 × 11^16
ii) Add powers together.
A×B = 2^6 × 3^10 × 5^4 × 7^2 × 11^16
sqrt(A × B)
Divide powers by 2.
sqrt(A × B) = 2^3 × 3^5 × 5^2 × 7 × 11^8
iii) C = 3^7 × 5^2 × 7
Ck = (3^7 × 5^2 × 7) × k
B/c Ck should be a product that is a perfect cube, the powers of the products should be divisible by 3.
(3^7 × 5^2 × 7) × k = 3^9 × 5^3 × 7^3
k = (3^9 × 5^3 × 7^3) / (3^7 × 5^2 × 7)
k = 3^(9-7) × 5^(3-2) × 7^(3-1)
k = 3^2 × 5 × 7^2