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Nesterboy [21]
3 years ago
10

Graph the system of linear equations. -1/2y=1/2x+5 and y=2x+2

Mathematics
1 answer:
sattari [20]3 years ago
4 0

Answer:

The point for the given linear equations is (\dfrac{-2}{3} , \dfrac{2}{3})

Step-by-step explanation:

Given as :

The two linear equations are

First equation

\dfrac{-1}{2} y = \dfrac{1}{2} x + 5

Or,  \dfrac{1}{2} y + \dfrac{1}{2} x + 5 = 0

Taking LCM we get

y + x + 10 = 0          .......1

Second equation

y = 2 x + 2               ........2

Now solving both equation

Putting the value of y from eq 2 into eq 1

(2 x + 2) + x + 10 = 0

Or, 3 x + 12 = 10

Or, 3 x = 10 - 12

Or, 3 x = - 2

∴  x = \dfrac{-2}{3}

Now putting the value of x into eq 2

∵ y = 2 x + 2              

Or, y = 2 × \dfrac{-2}{3} + 2

Or, y = \dfrac{-4}{3} + 2

Or, y = \dfrac{- 4 + 6}{3}

∴   y = \dfrac{2}{3}

So, The points are (x , y ) = (\dfrac{-2}{3} , \dfrac{2}{3})

Now, plotting the points on x-y coordinate graph

Hence, The point for the given linear equations is (\dfrac{-2}{3} , \dfrac{2}{3}) Answer

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Slope: \frac{3}{5}

Y-Intercept: (0,-5)

Step-by-step explanation:

1. To find the slope, we need to have the equation in slope-intercept form, which is y=mx+b. In this case, our equation is already in this form. m is what your slope is. In this case, our

2. To find the y-intercept we look at value b that is in y=mx+b. In this case, b is -5. So, our ordered pair is (0,-5).

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