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4 years ago

1 milligram (mg) is equal to how many micrograms (μg)?

Chemistry

2 answers:

Verizon [17]4 years ago

8 0

Answer:

e) 1000 μg

Explanation:

When we need to change of units is very important to know equivalence and use conversion factors to change from one unit to another unit.

1Ton = 1000Kg

1Kg = 1000g

1g = 1000mg

1mg = 1000 μg

In this case, always 1mg will be equal to 1000 μg as well as 2mg will be 1000μg

Margaret [11]4 years ago

5 0

Answer:

The answer is e. 1000

Explanation:

1 milligram has 1000 micrograms. If you want convert milligrams to micrograms just multiply by 1000. If you want convert micrograms to milligrams divide by 1000

I hope it helps

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Recall that your hypothesis is that these values are the fraction of atoms that are still radioactive after n half-life cycles.

jolli1 [7]

Answer : A= 0.5, B = 0.25 , C = 0.125, D = 0.015625 and E = 0.00390625

Explanation :

Half life of a substance is defined as the amount of time taken by the substance to reduce to half of its original amount.

Here n represents the number of half lives.

The amount of substance that remains after n half lives can be calculated using the given formula, $0.5^{n}$

So when we have n =1,

Fraction of substance that remains = 0.5¹ = 0.5.

That means after first half life over, the amount of substance that remains is 0.5 times that of original.

Therefore we have A = 0.5

When n = 2, we have 0.5² = 0.25

So when 2 half lives are over, the amount of substance that remains is 0.25 times that of original

Therefore B = 0.25

When n = 3, we have 0.5³ = 0.125

So when 3 half lives are over, the amount of substance that remains is 0.125 times that of original.

Therefore we have C = 0.125

When n = 6 , we have 0.5⁶ = 0.015625

So D = 0.015625

When n = 8, we have 0.5⁸ = 0.00390625

Therefore E = 0.00390625

The values for A, B, C, D and E are 0.5, 0.25, 0.125, 0.015625 and 0.00390625 respectively.

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4 years ago

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Compare and contrast the arrangement of particles at the atomic level for a liquid and a solid

galben [10]

Answer:

Liquid particles are farther apart than solid particles.

Explanation:

Liquid particles are more far apart than solid particles, explaining why it takes the shape of its container and does not have a definite shape, but has a definite volume. Solid particles are more tightly packed together, and certain solids even have particle patterns at the atomic level, which is why it has a definite shape and does not change unless it changes states.

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3 years ago

Which statement regarding nuclear and chemical reactions is not true?

Ksju [112]

The second one ,I hope I'm right .

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3 years ago

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Why is water a covalent bond

earnstyle [38]

Because hydrogen bonds with oxygen
H2O

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4 years ago

Consider the reaction C2H4(g) + H2O(g)CH3CH2OH(g) Using standard thermodynamic data at 298K, calculate the entropy change for th

Aleks [24]

<u>Answer:</u> The value of $\Delta S^o$ for the surrounding when given amount of ethene gas is reacted is 238.80 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$C_2H_4(g)+H_2O(g)\rightarrow CH_3CH_2OH(g)$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(1\times \Delta S^o_{(CH_3CH_2OH(g))})]-[(1\times \Delta S^o_{(C_2H_4(g))})+(1\times \Delta S^o_{(H_2O(g))})]$

We are given:

$\Delta S^o_{(CH_3CH_2OH(g))}=282.7J/K.mol\\\Delta S^o_{(C_2H_4(g))}=219.56J/K.mol\\\Delta S^o_{(H_2O(g))}=188.82J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(1\times (282.7))]-[(1\times (219.56))+(1\times (188.82))]\\\\\Delta S^o_{rxn}=-125.68J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(-125.68) J/K = 125.68 J/K

We are given:

Moles of ethene gas reacted = 1.90 moles

By Stoichiometry of the reaction:

When 1 mole of ethene gas is reacted, the entropy change of the surrounding will be 125.68 J/K

So, when 1.90 moles of ethene gas is reacted, the entropy change of the surrounding will be = $\frac{125.68}{1}\times 1.90=238.80J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of ethene gas is reacted is 238.80 J/K

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