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rodikova [14]
2 years ago
6

How many moles of oxygen atoms are present in 0.4 moles of oxygen gas​

Chemistry
2 answers:
Kitty [74]2 years ago
8 0

Answer:

Explanation:

Each molecule of O2 is made up of 2 oxygen atoms. So 1 mole of O2 molecules is made up of 2 moles of oxygen atoms. Therefore 1 mole of oxygen gas contains 2 moles of oxygen atoms. And 0.4 moles of oxygen gas contains 0.8 moles of oxygen atoms.

Agata [3.3K]2 years ago
4 0

Answer:

Each molecule of O2 is made up of 2 oxygen atoms. So 1 mole of O2 molecules is made up of 2 moles of oxygen atoms. Therefore 1 mole of oxygen gas contains 2 moles of oxygen atoms. And 0.4 moles of oxygen gas contains 0.8 moles of oxygen atoms.

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if you started with 2.34 grams of methane and 8.32 grams of oxeygyn and the combustion reaction went to completion how many gram
Romashka-Z-Leto [24]

Answer:

Mass of CO₂ produced  = 5.72 g

Explanation:

Given data:

Mass of methane = 2.34 g

Mass of oxygen = 8.32 g

Mass of CO₂ produced = ?

Solution:

Chemical equation:

CH₄ + 2O₂    →      CO₂ + 2H₂O

Number of moles of methane:

Number of moles = mass/molar mass

Number of moles =  2.34 g/ 16 g/mol

Number of moles = 0.146 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles =  8.32 g/ 32 g/mol

Number of moles = 0.26 mol

Now we will compare the moles of carbon dioxide with oxygen and methane.

                         CH₄             :              CO₂

                           1                 :              1

                        0.146            :           0.146

                         O₂                :               CO₂

                          2                 :                   1

                     0.26                :              1/2×0.26 = 0.13 mol

Less number of moles of CO₂ are produced by oxygen thus oxygen will react as limiting reactant.

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 0.13 mol ×  44 g/mol

Mass = 5.72 g

4 0
2 years ago
For water, the value for the latent heat of vaporization is 6.8 times greater than the latent heat of fusion. Imagine we were ad
Tom [10]

Answer:

Time of vaporization = 0.588 minutes

Explanation:

The latent heat of fusion is the heat required to change the substance from solid (ice) to liquid completely, without further increase in temperature.

The latent heat of vaporization is the heat required to change a liquid to gas completely, without an increase in temperature.

Latent heat of vaporization = 6.8 times Latent heat of fusion

This means that the time it takes for the latent heat of vaporization to complete vaporization is 6.8 times lesser than the time it takes for the latent heat of fusion to complete fusion

Time of vaporization = 6.8 times lesser than time of fusion

Time of vaporization = (time of fusion) ÷ 6.8

where: Time of fusion = 4 minutes

∴ Time of vaporization = 4 ÷ 6.8

Time of vaporization = 0.588 minutes

8 0
3 years ago
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