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3 years ago

Which of the following statements is normative rather than positive?

Business

1 answer:

torisob [31]3 years ago

7 0

Answer:

D) Income inequality should be minimized in a developed society.

Explanation:

Normative statements express value-based judgement on how a situation should be . In the instance aboce, it is the author's opinion that in developed society income inequality should be minimised.

Positive statements are more descriptive using facts to make statements. In the above Carla will get more excercise at the fair than at the movies is a fact-based statement.

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The Red Bud Co. pays a constant dividend of $2.40 a share. The company announced today that it will continue to do this for anot

ElenaW [278]

Answer:

$4.44

Explanation:

P0 = $2.40 / 1.08+ $2.40 / 1.08 = $4. 44

5 0

3 years ago

Aziz company sells two types of products, basic and deluxe. the company provides technical support for users of its products, at

Marta_Voda [28]

The company's cost per customer support call is 25 dollars.

Simply divide total costs by total calls to find the cost per call.

$250,000/ 10,000 calls = $25/ call

5 0

4 years ago

Currently, you owe the bank $9,800 for a car loan. The loan has an interest rate of 7.75 percent and monthly payments of $310. Y

Ostrovityanka [42]

Answer:

It will extend the loan for 15.83 months = 16 more months.

Explanation:

We need to calcualte the difference in time between one option and another:

Original Loan:

$C \times \frac{1-(1+r)^{-time} }{rate} = PV\\$

C $310.00

time n

rate 0.0064583 (0.0775annual rate / 12 month per year)

PV $9,800

$310 \times \frac{1-(1+0.0064583)^{-n} }{0.0064583} = 9800\\$

We rearrenge and solve as much as we can:

$(1+0.0064583)^{-n}= 1-\frac{9800\times0.0064583}{310}$

$(1+0.0064583)^{-n} = 0.79583439$

Now, we solve using logarithmics properties:

$-n= \frac{log0.795834387096774}{log(1+0.0064583)}$

35.47385568

Now we calcualte with the new terms:

C $225.00

$225 \times \frac{1-(1+0.0064583)^{-n} }{0.0064583} = 9800\\$

$(1+0.0064583)^{-n}= 1-\frac{9800\times0.0064583}{225}$

$(1+0.0064583)^{-n}= 0.71870516$

$-n= \frac{log0.718705155555555}{log(1+0.0064583)}$

51.30909653

Last step, we solve for the difference:

51.30 - 35.47 = 15.83 = 16 more months

7 0

3 years ago

Two items are omitted from each of the following summaries of balance sheet and income statement data for two proprietorships fo

bulgar [2K]

Answer:

The solution according to the given query is provided below.

Explanation:

The given question seems to be incomplete. The attachment of the complete query is provided below.

Now,

The additional investment will be:

= $Ending \ owner's \ equity-Beginning \ owner's \ equity+Drawings-Net \ income$

By putting the values, we get

= $40000-25000+37000-45000$

= $7,000$

Now,

The drawings will be:

= $Ending \ owner's \ equity-Beginning \ owner's \ equity+Additional \ investment-Net \ income$

By putting the values, we get

= $130000-80000-25000-40000$

= $-15,000$

3 0

3 years ago

Larry Ellison starts a company that manufactures high-end custom leather bags. He hires two employees. Each employee only begins

Degger [83]

Answer:

12.55 days

Explanation:

Provided information

Number of employees 2

Average production time=1.8 days

Standard deviation=2.7 days

Inter-arrival time= 1 day

Coefficient of variation= 1 day

Standard deviation of inter-arrival time= 1 day

The coefficient of variations

Inter-arrival coefficient of variation

$C_{vi}=\frac {\sigma}{T}$ where $\sigma$ is standard deviation of inter-arrival time, T is inter-arrival time and $C_v$ is coefficient of variation of inter-arrival time

$C_{vi}=\frac {1 day}{1 day}=1$

Production time coefficient of variation

$C_{vp}=\frac {2.7}{1.8}=1.5$

Total utilization time

$U=\frac {T}{n*T_i}$ where T is the time of production, n is number of employees, U is utilization, $T_i$ is inter-arrival time

$U=\frac {1.8}{2*1}=0.9$

Therefore, utilization time by 2 employees is 0.9

Expected average waiting time

$T_e=(\frac {T}{n*T_i})*0.5(C_{vi}^{2}+C_{vp}^{2})*(\frac{U^{\sqrt{2(n+1)}-1}}{1-U})$

Where $T_e$ is expected average waiting time and the other symbols as already defined

Substituting 1.5 for $C_{vp}$ , 1 for $C_{vi}$ , 0.9 for U, 2 for n, 1 for $T_i$ and 1.8 for T

$T_e=(\frac {1.8}{2*1})*0.5(1^{2}+1.5^{2})*(\frac{0.9^{\sqrt{2(2+1)}-1}}{1-0.9})$

$T_e=0.9*1.625*8.583709=12.55367 days$ and rounding off to 2 decimal places we obtain 12.55 days

Therefore, expected duration between order received and beginning of production is approximately 12.55 days

7 0

3 years ago