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Andrews [41]
3 years ago
7

Alice Correa bought three yards of cloth to make a dress. The cloth was on sale for $1.93 per yard.

Mathematics
1 answer:
Ray Of Light [21]3 years ago
4 0
Since the unit rate is $1.93 per yard, you need to multiply the number of yards by 1.93. So 1.93 x 3 = 5.79. Next, you convert 5% to a decimal, which is 0.05. Now, multiply 5.79 by 0.05, which is about 0.29. Finally, add 0.29 to 5.79, giving you the answer of 6.08. Alice payed $6.08; D.
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12 down is decagon. 7 down is mode. I think 5 down is slope. 13 down is prime. 3 down might be variable. 10 down should be equation. Hope these are right!
7 0
4 years ago
Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos
crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c)  P(X = 2) is unusual, P(X = 0) is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

A number of sucesses x is considered unusually low if P(X \leq x) \leq 0.05 and unusually high if P(X \geq x) \geq 0.05

In this problem, we have that:

Two cans are randomly chosen, so n = 2

Two out of 18 cans are filled with diet coke, so \pi = \frac{2}{18} = 0.11

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that P(X = 2) is unusual, since P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958

There is a 19.58% probability that exactly one is diet and exactly one is regular.

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3 years ago
A set of math tests is normally distributed
Masteriza [31]

Answer:

wat is the actual question for this??

Step-by-step explanation:

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An item has increased by<br> 23% to £58.<br> What was the original<br> price?
yKpoI14uk [10]

Answer:

The answer is 44.66

Step-by-step explanation:

Multiply 58 by 0.23. This will give you 13.34. Next, you subtract this from 58 to get your original price.

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What are two different ways you can show 103?
valina [46]

Answer:

100+3, a hundred three.

Step-by-step explanation:

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3 years ago
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