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3 years ago

Are 17 heartbeats in 15 seconds and 68 heartbeats in 60 seconds Equivalent

Mathematics

2 answers:

Andre45 [30]3 years ago

4 0

Answer:

1.133.

Step-by-step explanation:

Yes because if you divide 17 by 15 you get about 1.133 and if you divide 68 by 60 you also get about 1.133.

vampirchik [111]3 years ago

4 0

Answer:

Step-by-step explanation:

17/15 = 1 2/15

68/60 = 1 2/15

yes, they are equivalent

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A band expects to put 12 songs on their next CD. The band writes and records 25% more songs than they expect to put on the CD.

sweet-ann [11.9K]

12 songs. 25% of 12 is 3, so you add 3 to 12 and get 15. You then find that 20% of 15 is 3 so you subtract 3 from 15 and get 12 again.

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3 years ago

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Help pls also show work if needed!

neonofarm [45]

Answer AND Step-by-step explanation:

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#teamtrees #PAW (Plant And Water)

The equation is:

$c = -\frac{1}{2} t + 6$

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3 years ago

The cosine law

romanna [79]

$\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-------------------------------\\\\$

$\bf \cfrac{sin(88^o)}{39.9}=\cfrac{sin(A)}{31}\implies \cfrac{31\cdot sin(88^o)}{39.9}=sin(A)
\\\\\\
sin^{-1}\left[ \cfrac{31\cdot sin(88^o)}{39.9} \right]=sin^{-1}\left[ sin(A) \right]
\\\\\\
sin^{-1}\left[ \cfrac{31\cdot sin(88^o)}{39.9} \right]=\measuredangle A
\\\\\\
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3 0

3 years ago

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$