0.1/2 as a decimal plz help

D= number of dollars

padilas [110]

Unit rate 4:

The table

d n

4 1

8 2

16 4

Unit rate 1/4:

Table

d n

1 4

4 16

16 64

and

The equation n=4d

Unit rate 16:

Equation:

d = 16n

Step-by-step explanation:

The unit in the unit rate is dollars per unit ounces which means that the unit rate calculated by

$Unit\ rate = \frac{dollars}{ounces}$

So,

The first option is the equation:

$d = 16n\\\frac{d}{n} = 16$

The unit rate is 16 dollars per ounce

The second option is the table:

d n

1 4

4 16

16 64

We can take any pair of values of d and n from the table to calculate the unit rate

So taking

d = 1

n=4

$Unit\ rate = \frac{d}{n}\\= \frac{1}{4}$

The unit rate for table is: 1/4 dollars per ounces

Third option is the equation:

n = 4d

$n = 4d$

dividing both sides by n

$\frac{n}{n} = \frac{4d}{n}\\1 = \frac{4d}{n}$

dividing both sides by 4

$\frac{1}{4} = \frac{4d}{4n}\\\frac{d}{n} = \frac{1}{4}$

the unit rate is 1/4 dollars per ounce

Fourth option is the table:

d n

4 1

8 2

16 4

We will take any pair of d and n to find the unit rate

So,

Taking

d = 4

n =1

$Unit\ rate = \frac{d}{n} \\= \frac{4}{1}\\=4$

The unit rate is 4 dollars per unit ounce.

Keywords: Unit rate, units

Learn more about unit rate at:

#LearnwithBrainly

7 0

3 years ago

Diana received 300 votes in the election for student council president. That was 60% of the students who voted in the election.

Helen [10]

Answer:

500 students.

Step-by-step explanation:

300 votes is 60%.

100%-60% is 40%

so 40% voted for the other person.

Work backwards:

x * 0.6=300

0.6x=300

x=300/0.6 which is 500.

500*0.4 is 200.

300+200 is 500.

Hope this helps :) I am terribly sorry if it is wrong or not using the number line.

7 0

3 years ago

Solve for x. Each figure is a parallelogram.

Yuki888 [10]

Answer:

A)4

Step-by-step explanation:

degree measure of the 4 angles of a trapezoid is 360

so

since we have only 2 angles, 360/2

180=125+(14x-1)

180-125=125+(14x-1)-125

55=14x-1

55+1=14x-1+1

56=14x

4=x or x=4

hope this helps!

6 0

3 years ago

Read 2 more answers

Give the most precise selection

inn [45]

Answer:

Its definitley square to be precise so that's my answer, but its also a rhombus

Step-by-step explanation:

assuming a is 1, regardless, graph would always be square, which is a rhombus. hope square is correct :)

7 0

3 years ago

The ages of students enrolled in two math classes at the local community college, Class A and Class B, are listed in order below

nlexa [21]

Answer:

The true statement about Class B is that Class B has a smaller median and the same inter quartile range.

Step-by-step explanation:

We are given the ages of students enrolled in two math classes at the local community college, Class A and Class B, below;

Class A: 20, 20, 20, 21, 22, 23, 23, 25, 27, 29, 30, 31, 34, 35, 36, 39, 40

Class B: 16, 17, 18, 18, 20, 22, 22, 24, 26, 26, 28, 29, 30, 34, 37, 40, 42

1) Firstly, we will calculate Median for Class A;

For calculating median, first we have to observe that number of observations (n) in our data is even or odd, that is;

If n is odd, then the formula for calculating median is given by;

Median = $(\frac{n+1}{2})^{th} \text{ obs.}$

If n is even, then the formula for calculating median is given by;

Median = $\frac{(\frac{n}{2})^{th} \text{ obs.}+(\frac{n}{2}+1)^{th} \text{ obs.}}{2}$

Here, number of observation is odd, i.e. n = 17.

So, Median = $(\frac{n+1}{2})^{th} \text{ obs.}$

= $(\frac{17+1}{2})^{th} \text{ obs.}$

= $(\frac{18}{2})^{th} \text{ obs.}$

= $9^{th} \text { obs.}$ = 27

Hence, the median of class A is 27.

2) Now, we will calculate Median for Class B;

For calculating median, first we have to observe that number of observations (n) in our data is even or odd, that is;

If n is odd, then the formula for calculating median is given by;

Median = $(\frac{n+1}{2})^{th} \text{ obs.}$

If n is even, then the formula for calculating median is given by;

Median = $\frac{(\frac{n}{2})^{th} \text{ obs.}+(\frac{n}{2}+1)^{th} \text{ obs.}}{2}$

Here, number of observation is odd, i.e. n = 17.

So, Median = $(\frac{n+1}{2})^{th} \text{ obs.}$

= $(\frac{17+1}{2})^{th} \text{ obs.}$

= $(\frac{18}{2})^{th} \text{ obs.}$

= $9^{th} \text { obs.}$ = 26

Hence, the median of class B is 26.

3) Now, we will calculate the Inter quartile range for Class A;

Inter quartile range = Upper quartile - Lower quartile

= $Q_3-Q_1$

SO, $Q_1 = (\frac{n+1}{4})^{th} \text{ obs.}$

= $(\frac{17+1}{4})^{th} \text{ obs.}$

= $(\frac{18}{4})^{th} \text{ obs.}$

= $4.5^{th} \text{ obs.}$

= $4^{th} \text{ obs.} + 0.5[5^{th} \text{ obs.} - 4^{th} \text{ obs.}]$

= $21+ 0.5[22- 21]$

= 21.5

Similarly, $Q_3 = 3(\frac{n+1}{4})^{th} \text{ obs.}$

= $3(\frac{17+1}{4})^{th} \text{ obs.}$

= $(\frac{54}{4})^{th} \text{ obs.}$

= $13.5^{th} \text{ obs.}$

= $13^{th} \text{ obs.} + 0.5[14^{th} \text{ obs.} - 13^{th} \text{ obs.}]$

= $34+ 0.5[35- 34]$

= 34.5

Therefore, Inter quartile range for Class A = 34.5 - 21.5 = 13.

4) Now, we will calculate the Inter quartile range for Class B;

Inter quartile range = Upper quartile - Lower quartile

= $Q_3-Q_1$

SO, $Q_1 = (\frac{n+1}{4})^{th} \text{ obs.}$

= $(\frac{17+1}{4})^{th} \text{ obs.}$

= $(\frac{18}{4})^{th} \text{ obs.}$

= $4.5^{th} \text{ obs.}$

= $4^{th} \text{ obs.} + 0.5[5^{th} \text{ obs.} - 4^{th} \text{ obs.}]$

= $18+ 0.5[20- 18]$

= 19

Similarly, $Q_3 = 3(\frac{n+1}{4})^{th} \text{ obs.}$

= $3(\frac{17+1}{4})^{th} \text{ obs.}$

= $(\frac{54}{4})^{th} \text{ obs.}$

= $13.5^{th} \text{ obs.}$

= $13^{th} \text{ obs.} + 0.5[14^{th} \text{ obs.} - 13^{th} \text{ obs.}]$

= $30+ 0.5[34- 30]$

= 32

Therefore, Inter quartile range for Class B = 32 - 19 = 13.

Hence, the true statement about Class B is that Class B has a smaller median and the same inter quartile range.

4 0

4 years ago