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hram777 [196]
3 years ago
7

What number is 12 more than -360?

Mathematics
1 answer:
const2013 [10]3 years ago
5 0
-348 I believe. It would be -360+12
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Wendy scores 24 points in a basketball game. If all of her baskets were 3-point shots, how many baskets did she make?
yarga [219]
Hello!

If all her shots were 3 pointers we will just divide

24÷3=8

Wendy made 8 baskets.

I hope this helps!
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Suppose someone tells you that she has a triangle with sides having lengths 3.5, 4.5 and 5.5 yards. Is this a right triangle?
Katarina [22]
You can solve by using Pythagoras theorem.
Let the longest side be c.
a^2 + b^2 = c^2
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3 years ago
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Write the sum in standard form <br><br> B) f(x)-h(x)
VLD [36.1K]

Answer:

Step-by-step explanation:

f(x) -h(x) = x³ + 2x² -7x - 8 - [4x² - x - 15 ]

             = x³ + 2x² - 7x - 8 - 4x² + x + 15

              = x³ + 2x² - 4x² - 7x + x - 8 + 15

              = x³ - 2x² - 6x + 7

8 0
2 years ago
If a factory continuously dumps pollutants into a river at the rate of the quotient of the square root of t and 45 tons per day,
julsineya [31]
<h2>Hello!</h2>

The answer is:

The first option, the amount dumped after 5 days is 0.166 tons.

<h2>Why?</h2>

To solve the problem, we need to integrate the given expression and evaluate using the given time.

So, integrating we have:

\int\limits^5_0 {\frac{\sqrt{t} }{45} } \, dt=\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \, dt\\\\\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \ dt=\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt\\\\\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt=(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)\\\\(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)=(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)

(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)=(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)\\\\(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)=(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)\\\\(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)=(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})\\\\(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})=\frac{2}{135}*11.18-0=0.1656=0.166

Hence, we have that the amount dumped after 5 days is 0.166 tons.

Have a nice day!

5 0
4 years ago
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