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shtirl [24]
3 years ago
14

WILL MARK BRAINLIEST A satellite is to be put into an elliptical orbit around a moon as shown below. A vertical ellipse is shown

surrounding a spherical object labeled, moon. The moon is a sphere with radius of 567 km. Determine an equation for the ellipse if the distance of the satellite from the surface of the moon varies from 900 km to 169 km. x squared divided by 900 plus y squared divided by 169 = 1 x squared divided by 1467 squared plus y squared divided by 736 squared = 1 x squared divided by 736 squared plus y squared divided by 1467 = 1 x squared divided by 169 plus y squared divided by 900 = 1
Mathematics
1 answer:
Radda [10]3 years ago
7 0

Answer:

a=567 km+900 km

a=1,467 km

b=567 km+169 km

b=736 km

x^2/a^2+y^2/b^2=1

x^2/(1,467)^2+y^2/(736)^2=1

Step-by-step explanation:

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3 years ago
a mechanic worked 20 hours. another mechanic worked 15 hours. together they charged a total of $1950. what was the rate charged
Natasha_Volkova [10]

Answer: The mechanics both charged $70 and $45 per hour respectively

Step-by-step explanation: We shall start by calling the mechanics hourly rates x and y respectively. So if one worked for 20 hours and charged 20 times x dollars, and the other one worked for 15 hours and charged 15 times y dollars, totalling 1950 dollars, we can write the following expression,

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Also, if the sum of the two rates was 115 dollars, that means for working for an hour only, they both would earn

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We now have a pair of simultaneous equations

20x + 15y = 1950 --------(1)

x + y = 115 ------------------(2)

We shall use the substitution method for this problem.

From equation (2), make x the subject of the equation

x = 115 - y

Substitute for the value of x into equation (1)

20(115 - y) + 15y = 1950

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By collecting like terms we now have

2300 - 1950 = 20y - 15y

(Note that when a negative value crosses to the other side of the equation, it becomes a positive value and vice versa)

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Divide both sides of the equation by 5

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We now substitute for the value of y into equation (2)

x + y = 115

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Subtract 70 from both sides of the equation

x = 45.

Therefore, the rate they charged per hour were $45 and $70 respectively.

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