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3 years ago

3. (02.02 MC)

Mathematics

1 answer:

LenaWriter [7]3 years ago

8 0

Answer:

O -1+ 3/

Step-by-step explanation:

brainest plz

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I need help with math please explain or show how to do t

slamgirl [31]

Answer:

B t = 9(5)

Step-by-step explanation:

for each mile the time increased by 9 minutes. So you can find the time in minutes by multiplying the number of miles by 9.

5 0

3 years ago

5. An attacker swings a board with a mass of 2 kg toward a victim. The acceleration is 10 m/s2 when the board hits the victim. H

suter [353]

The force exerted on victim is 20 newton

Solution:

An attacker swings a board with a mass of 2 kg toward a victim

The acceleration is 10 $m/s^2$ when the board hits the victim

To find: Force exerted on victim

The force is given by formula:

$F = mass \times acceleration$

From given,

$mass = 2 \text{ kg }\\\\Acceleration = 10$ $m/s^2$

Substituting the values in formula,

$Force = 2 \times 10 = 20$

Thus force exerted on victim is 20 newton

6 0

3 years ago

Help help help help help

Dmitriy789 [7]

25/4
You can multiply by crossing
10/24 and x/15
10*15 = 24x
150/24=x
Divide the numerator and denominator by 6
25/4
25/4 is the answer

6 0

3 years ago

The width of a rectangle is 15 cm and the perimeter is 72 cm. Find the length.

ale4655 [162]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The triangles below are similar. Triangle A B C. Side A C is 10 and side A B is 5. Angle C is 30 degrees. Triangle D E F. Side E

Gnoma [55]

Answer:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

$\triangle BAC {\displaystyle \sim } \triangle EDF$

Step-by-step explanation:

Given

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$AC = 10$

$AB = 5$

$\angle C = 30^\circ$

$ED = 7.5$

$DF = 25$

$\angle F =30$

$\angle E =90$

Required

Which of the options is/are true:

$\triangle CBA {\displaystyle \sim } \triangle FED$ $\triangle CBA {\displaystyle \sim } \triangle FDE$ $\triangle BAC {\displaystyle \sim } \triangle EFD$

$\triangle BAC {\displaystyle \sim } \triangle EDF$ $\triangle ABC {\displaystyle \sim } \triangle DE\ F$ $\triangle ABC {\displaystyle \sim } \triangle DFE$

The given triangles, implies that:

$A {\displaystyle \sim } \ D$

$B {\displaystyle \sim } \ E$

$C {\displaystyle \sim } \ F$

By taking each sides of both triangle, one after the other; the possible similar triangles are:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

$\triangle BAC {\displaystyle \sim } \triangle EDF$

5 0

3 years ago