![f(x)=-x^2+1](https://tex.z-dn.net/?f=f%28x%29%3D-x%5E2%2B1)
Plug in the value
into this function
![f(-3)=-(-3)^2+1](https://tex.z-dn.net/?f=f%28-3%29%3D-%28-3%29%5E2%2B1)
![=-(9)+1](https://tex.z-dn.net/?f=%3D-%289%29%2B1)
![=-8](https://tex.z-dn.net/?f=%3D-8)
Thus, your answer will be D) -8. Let me know if you need any clarifications, thanks!
Answer:
-8x
Step-by-step explanation:
Answer:
y=6x−10
Step-by-step explanation:
Answer:
Question 1 (1 point)
1. An object has a mass of 25g and a volume of 5ml
a
10
b
8
c
5
d
7
Question 2 (1 point)
2. An object has a mass of 30g and a volume of15ml. What is the density?
a
10
b
2
c
3
d
5
Question 3 (1 point)
3. An object has a mass of 200g and a volume of 100ml. What is the density?
a
2
b
4
c
6
d
8
Question 4 (1 point)
4. An object has a mass of 17g and a volume of 2ml. What is the density?
a
2.4
b
2
c
8
d
8.5
Question 5 (1 point)
5. An object has a mass of 20g and a volume of 5ml. What is the density?
a
2
b
4
c
10
d
2.5
Question 6 (1 point)
6. An object has a mass of 75g and a volume of 75ml. What is the density?
a
6
b
1
c
7
d
8
Question 7 (1 point)
7. An object has a volume of 100ml and a mass of 2oo ml. What is the density?
a
0.5
b
1
c
4
d
2.5
Question 8 (1 point)
8. An object has a volume of 5ml and a mass of 650 g. What is the density?
a
110
b
120
c
130
d
200
Question 9 (1 point)
9. An object has a mass of 15g and a volume of 5ml. What is the density?
a
2.5
b
7
c
3
d
2.56
Question 10 (1 point)
10. An object has a mass of 13g and a volume of 2ml. What is the density?
a
6.5
b
3.7
c
4
d
Step-by-step explanation:
Given:
The bases of triangular prism are right triangles with a base of 12 inches and height of 9 inches.
The height of the prism is 11 inches.
To find:
The surface area of the triangular prism.
Solution:
Using the Pythagoras theorem, the hypotenuse of the bases of the triangular prism is:
![Hypotenuse^2=Base^2+Height^2](https://tex.z-dn.net/?f=Hypotenuse%5E2%3DBase%5E2%2BHeight%5E2)
![Hypotenuse^2=12^2+9^2](https://tex.z-dn.net/?f=Hypotenuse%5E2%3D12%5E2%2B9%5E2)
![Hypotenuse^2=144+81](https://tex.z-dn.net/?f=Hypotenuse%5E2%3D144%2B81)
![Hypotenuse^2=225](https://tex.z-dn.net/?f=Hypotenuse%5E2%3D225)
Taking square root on both sides.
![Hypotenuse=15](https://tex.z-dn.net/?f=Hypotenuse%3D15)
The surface after of the triangular prism contains 3 rectangles of dimensions 12 inches by 11 inches, 9 inches by 11 inches, 15 inches by 11 inches and two triangles with base 12 inches and height 9 inches.
Area of the rectangle:
![Area=Length \times Width](https://tex.z-dn.net/?f=Area%3DLength%20%5Ctimes%20Width)
So, the area of three rectangles are:
![A_1=12 \times 11](https://tex.z-dn.net/?f=A_1%3D12%20%5Ctimes%2011)
![A_1=132](https://tex.z-dn.net/?f=A_1%3D132)
![A_2=9 \times 11](https://tex.z-dn.net/?f=A_2%3D9%20%5Ctimes%2011)
![A_2=99](https://tex.z-dn.net/?f=A_2%3D99)
![A_3=15 \times 11](https://tex.z-dn.net/?f=A_3%3D15%20%5Ctimes%2011)
![A_3=165](https://tex.z-dn.net/?f=A_3%3D165)
Area of a triangle is:
![Area=\dfrac{1}{2}\times base \times height](https://tex.z-dn.net/?f=Area%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20base%20%5Ctimes%20height)
So, the area of the triangles is:
![A_4=\dfrac{1}{2}\times 12 \times 9](https://tex.z-dn.net/?f=A_4%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%2012%20%5Ctimes%209)
![A_4=6 \times 9](https://tex.z-dn.net/?f=A_4%3D6%20%5Ctimes%209)
![A_4=54](https://tex.z-dn.net/?f=A_4%3D54)
And, the triangles have same dimensions so their areas are equal.
![A_4=A_5=54](https://tex.z-dn.net/?f=A_4%3DA_5%3D54)
Now,
![Area=A_1+A_2+A_3+A_4+A_5](https://tex.z-dn.net/?f=Area%3DA_1%2BA_2%2BA_3%2BA_4%2BA_5)
![Area=132+99+165+54+54](https://tex.z-dn.net/?f=Area%3D132%2B99%2B165%2B54%2B54)
![Area=504](https://tex.z-dn.net/?f=Area%3D504)
Therefore, the surface area of the triangular prism is 504 sq. inches.